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Explain Euler's Theorem/Identity 
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#37
Jun2111, 02:10 PM

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If you mean you are troubled by the fact that you do not comprehend complex numbers, I can understand that but surely that can be easily remedied. 


#38
Jun2711, 10:00 AM

P: 8

I am sorry.
I had looked at Euler's as a trig function where i doesn't seem to have much of a role. Had I looked at it as literally the limit of (1+zi/n)^n, nothing else besides i works at all. Again, sorry for my narrow view of the topic. 


#39
Aug1911, 11:22 AM

P: 8

Hootanany; I did mistate when I said the 'value of i is zero', it probably should've read 'the coefficient of i is zero', or 'the imaginary part is zero' or something. That would've been clearer to my point. Point of fact; the imaginary part of the solution to e^iPi is in fact zero. It is not complex.
In Re; HallsofIvy; I am pretty sure I understand the complex plane. Your assertion that I do not is a bit insulting. But, since you didn't insult me adhominem, but did question my understanding of the basic concept of complex numbers, I will likewise take you to task; You stated; "There is no angle and no coefficient here." Not sure how you defend that. By denying that there is in fact an angle, and that the coefficient of that angle is i, you demonstrate a rather thin understanding of Euler's identity. I don't know what place you have acting as an authority on this topic at all. Whereas I simply failed to evaluate Euler's identity as an infinite polynomial (limit), rather than a trig. function, you have failed to recognize that it springs from Euler's formula which inherently and explicitly involves angles and a coefficient of i. It is hard to take the sine or cosine of something that isn't an angle. Euler's formula converts cartesian coordinates to polar coordinates in the imaginary plain. Can you elaborate how this is possible without angles? You can derive Eulers Identity without using limits. You cannot derive it without the formula though. The complex plane is simple enough to be understood by most 9th graders. I am pretty sure everyone visiting this message board gets that. To state that I do not is a thinly veiled insult. In the end; I feel confident in my comprehension of the issues at hand, but I think you've demonstrated yours is lacking. 


#40
Aug1911, 11:54 AM

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#41
Aug2211, 01:51 PM

P: 192

Bob Kutz, what you said is not not strictly speaking true. You said that if "i" is relaced with anything in the formula, then it follows that [itex]e^{anything*x}=1[/itex]. However, it is not a property of "anything" (even any mathematical object) that anything*0=0. This is a property of real and complex numbers. The operation of "multiplying a real number by a unicorn" is not well defined. The operation of "multiplying a real number by a complex number," however, is.



#42
Aug2211, 03:31 PM

P: 8

Steve,
"The imaginary part of i" is an odd construct and a misuse of what I said. In Euler's Identity, there is no imaginary part at all in the solution. e^ipi + 1= 0. It certainly does not equal 0+i. So you've misread what I said or misunderstand the discussion. Again and for clarity; e^ipi +1 = 0 It does not equal 0 + i, so the imaginary part is in fact not 1. In fact, to your precise statement "the imaginary part of i is 1" does not even make sense. i is imaginary b/c i^2 = 1 and nobody had been able to define a real number that satisfies i. 1 is not imaginary, and in Euler's Identity the imaginary component is in fact zero, not one. As to the notion that zero is a complex number; do you mean in the sense that all real numbers are a subset of the complex numbers? I always thought of complex numbers as an extention to the real numbers, but what ever. The imaginary component in Euler's identity is still zero. If you wish to invoke the complex plane to solve cos (pi) + i sin(pi) then God bless, but you don't need to. Sin of pi is zero, the solution rests on the real number line. Alexfloo; As to the notion you cannot multiply a real number by a unicorn; would you object, then if I multiplied a real number (say 5) by cow and had five cows? That is the underlying math, is it not? I think real numbers multiplied by ordinary (or even imaginary) objects is quite well defined. That is where math came from, you know. You can certainly multiply real numbers by imaginary things, or this whole topic is a waste. As I said in the earlier post; my mistake was in evaluating Eulers based on it's derived formula rather than as a function of the natural log; the limit of (1+zi/n)^n. THAT is where i comes into it's own; if you don't have an i component, it doesn't make any sense at all. THAT is where Euler's goes from being a mathematical oddity to being truly transcendental. When evaluating it as a trigonometric function, i plays no important role other than as the scale of the y axis. As I said; could be anything, really, equation works just the same. And I am not sure you are correct that 'it is not a property of "anything" (even any mathematical object) that anything*0=0.' Isn't it? Is it not actually a mathematical property that for any x, x(0) = 0? From some unimportant website; Zero element Any number multiplied by zero is zero. This is known as the zero property of multiplication: x(0) = 0 Let x be a number. Or let it be boxes, ballots, cows or unicorns. If you have zero of them then you don't have any. If you have one and multilply it by 5, then you have 5. Say you have 5 boxes, and they're empty, then you multiply those boxes by zero; well then, you no longer have any boxes, do you? That is pretty rudimentary stuff right there. I thought we were well beyond all that, talking about Euler's formula and equation and all. 


#43
Aug2211, 03:36 PM

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What is the definition of [tex]e^{\pi *\text{cow}}[/tex] ? 


#44
Aug2211, 03:52 PM

P: 192

"And I am not sure you are correct that 'it is not a property of "anything" (even any mathematical object) that anything*0=0.' Isn't it? Is it not actually a mathematical property that for any x, x(0) = 0?"
This is not true. 0 times any twobytwo matrix is not zero, it's a matrix of zeros. The rule you're discussing is a property of NUMBERS as the page you cited states. "If you wish to invoke the complex plane to solve cos (pi) + i sin(pi) then God bless, but you don't need to. Sin of pi is zero, the solution rests on the real number line." This on the other hand is not wrong, it just completely misses the point. Euler's formuls isn't there for "solving cos (pi) + i sin(pi)," it's a much more profound and general statement about a relationship between two important functions on the complex plane. 


#45
Aug2211, 03:55 PM

P: 192

To reiterate, the point is not that:
cos (pi) + i sin(pi) = 1 This, as you've correctly stated many times, is trivial. The point is that: [itex]e^{i\pi}=1[/itex] which is *not* trivial, and is in fact a very interesting fact. 


#46
Feb1512, 12:04 PM

P: 1

I came across Lakoff's book "where math comes from" in which there's a section devoted to explain the meaning of the Identy instead of using a "tautology" that is generally given by many a professors, text books, intimidators, etc. They almost succeeded in making me understand, but at the last moment they also fall victim to using such vague qualities such as"periodicity", "rate of change" mumbo/jumbo that I feel an intuitive understanding is still lacking. Most people will tell U that it is because it equals cos x + i sinx or because e^xi happens to equal taylor expansion when sin and cos terms are added with a complex number twist lol, yeh but why?
The best way to understand it comes first, from khalid's "betterexplained" plus page of songho ahn's where a unit helix in 3d is shown with an img, real, and an X axis respectively(where x is just a linear axis representing the angle truncated at 2PI. Khalid's explained http://betterexplained.com/articles/...#comment53478 e^x as growth(as in compound int) > lim (1+1/n)^n and x represents rate/duration mix because e is the no. when u set n to infin of instantaneous 100% compounding. Similar with the unit circle, e^0 first grows to 1x the base e ( the radius), then because of the part i in the exp and where the rate of e^x change is just e^x as a def. Then the radius R is like a vector of unit length driven by a const i vector perpen to it (i.R is vel or accel if u will,moving counterclockwise at unit increments). And, note ln(x) means at what rate/period is needed to reach x time growth in e base. In Anh's page, http://www.songho.ca/math/euler/euler.html he sets ln(cosx+isinx) = xi, then cosx+isinx = e^xi so xi is the rate/period needed to reach position cosx+isinx. Now although with e^xi ,x as an angle is a very convenient indication of the position of the radius, it is hard to see how this exp resolves to something like .5678+ .8790i proportion as an example. Evidently, it is a result of the trig function and xi has a different ratio of the vertical vs horizontal depending on where the radius is pointed at along the circle, meaning different slope/tangent. So at any pos there is a changing rate of growth with regards both axes, but only in angles, not in length. On Anh's page , the 3D diag would dispel a lot of confusion generated by using imaginary no. Actually, with 2 extra dimensions, imag no. is just a math convenience to make sure U don't add the two nos as though they are both real and to deal with the sign when phase changes. So if U notice, the projection on the xReal plane is the Cos function tracing how the real shrinks and grow as the Imgx plane shadows a sin function showing how it grows and shrink on a complementary rate tracing a helix, but a 2D circle projection on the ImgReal plane. 


#47
Feb1512, 11:37 PM

P: 206

"Labeling i as imaginary is just nonsense, because it does exist."
That was a hoot. 


#48
Feb1512, 11:58 PM

P: 206

Historically, much of abstract mathematics is motivated by a desire to generalize familiar concepts and Euler's formula can be justified the same way. Suppose we seek a generalization of the exponential function to the complex plane. That is we seek a function f such that df/dz=f for all z, f is entire, and f=e^x on the real line, i.e. when y=0. Clearly f=(e^x)cosy+i(e^x)siny satisfies these requirements so we may define f=e^z. Now when z=iy is purely imaginary the result is Euler's formula. Proof? Maybe, maybe not, but it is an interesting historical justification.



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