
#1
Nov2011, 11:51 AM

P: 9

Im having trouble rearranging an equation to find a value for I.
[The given equation is mgh = 1/2*Iw^2 + 1/2*mv^2 + Tf * theta My attempt was a bit of a stab in the dark as i am useless with rearranging equations. I = mgh/w^2 + 1/2*mv^2 + Tf * theta Many thanks 



#2
Nov2011, 12:09 PM

P: 939

To make I subject of the equation is like peeling an onion.
First step: Transfer those two terms on the RHS not involving I to the LHS. 



#3
Nov2011, 01:09 PM

P: 9

ok so you end up with
mgh  1/2*mv^2  Tf*theta = 1/2*Iw^2 Would the lhs be divided by 1/2 w^2? Thanks 



#4
Nov2011, 02:04 PM

P: 939

Help needed with rearranging an equation
Yes we 'peel the next layer of the onion' by dividing BOTH sides by [itex]\frac{\omega^{2}}{2}[/itex] to isolate the I by itself on the RHS.




#5
Nov2311, 01:01 PM

P: 9

Nice one cheers



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