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Second derivative |
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| Feb20-12, 09:43 PM | #1 |
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Second derivative
http://www.math.northwestern.edu/cou..._Placement.pdf
Question 7 here involves a function with the rule f(x) = 3x5-5x3. I computed the 2nd derivative as f''(x) = 60x3-30x (Mathematica agrees.), giving inflection points for f at -1/sqrt(2), 0, 1/sqrt(2). But the answer given in the PDF is 4x(4x2 - 3), whence they conclude the inflection points are -sqrt(3)/2, 0, sqrt(3)/2. Is this a mistake, or have I overlooked something? |
| Feb21-12, 01:36 AM | #2 |
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You are right, and that is btw not the only mistake in that pdf.
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| Feb21-12, 09:11 AM | #3 |
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Thanks for confirming that, Norwegian. Could you tell me any others, or do you know if there's a list of errata anywhere online?
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| Feb21-12, 01:10 PM | #4 |
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Second derivative
1d, derivative of ln(..) seems wrong, probably more mistakes too
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| Feb21-12, 02:14 PM | #5 |
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Oh yes, wow, so it is! The derivative of ln(2t3-1) is 6t2/(2t3-1), not 6t2/(ln(2t3-1)). When I was checking my answers for those simple ones at the beginning and saw they had something slightly different for 1d, I just assumed it was a typo on my part and didn't look that closely.
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