Cyclic Permutation in C

TheSourceCode

Use nested for loops to produce the following pattern of cyclic permutations of the English
alphabet:
abcde......yz
bcdef......za
cdef......zab
...
zabcde......xy
HINT: you may find the modulo (remainder) operator % useful.

I have an idea of how to do this but it would not use the modulo operator. I thought of saving the first letter of an array into a variable, shifting everything else down one and putting it at the end. This also would only implement a single for loop. Any clues would be greatly appreciated.

Joffan

Yes, there are probably a million ways to do this, but I suggest that you have one loop generating the first character of each string and an inner loop (since that what was asked for) generating the successive letters of each string - using modulo operator to make the wrap from z to a.

TheSourceCode

Thanks a lot. Took me a bit to get the wrap around to work properly but I got it. I don't think modulo was very intuitive to me before but now I get it.

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Joffan	Yes, there are probably a million ways to do this, but I suggest that you have one loop generating the first character of each string and an inner loop (since that what was asked for) generating the successive letters of each string - using modulo operator to make the wrap from z to a.

TheSourceCode	Thanks a lot. Took me a bit to get the wrap around to work properly but I got it. I don't think modulo was very intuitive to me before but now I get it.