Register to reply 
Base 2 trouble 
Share this thread: 
#1
Feb2412, 05:53 PM

P: 64

I'm a little embarrassed by this and having a total brain fart.
I understand: (6 * 10^3) + (3 * 10^2) + (5 * 10^1) + (7 * 10^0) = 6000 + 300 + 50 + 7 = 6357 But for some reason I can't get this: (1 * 2^3) is equal to 8. (1 * 2^3) + (0 * 2^2) + (1 * 2^1) + (1 * 2^0) = 8 + 0 + 2 + 1 = 11 


#3
Feb2412, 06:05 PM

P: 64

http://computer.howstuffworks.com/bytes1.htm Its a page I came across while searching for more information. I did know how to work it out but have forgotten. 


#4
Feb2412, 06:07 PM

P: 15,319

Base 2 trouble
What you started with was 2^3 which is 1000 which is 8 Hey lookit that. I can look down and see Berkeman slooooooowly tyyyyping away..... 


#5
Feb2412, 06:08 PM

Mentor
P: 40,649

Below that do you see "8 = 1000" listed? 


#7
Feb2412, 06:46 PM

P: 64

OK, thank you guys I understood :).



#8
Feb2412, 07:21 PM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,301

1*2^3= 1*(2*2*2)= 1*(2*(2*2)). 2*2= 4 so that becomes 1*(2*4). 2*4= 8 so that becomes 1*8= 8. 


#9
Feb2412, 08:04 PM

P: 64

I was having trouble working out why 2^3=8. As simple as it seems. I haven't done any sort of to the power maths in years and it skipped my mind. But yes, you had answered my question, thank you. But ignoring the 1 in 1 * 2^3 as it was simply telling what binary digit 2^3 was representing. 


#10
Feb2412, 08:07 PM

P: 1,781

There are 10 kinds of people in the world. Those who read binary and those who don't.



#11
Feb2512, 12:29 AM

Mentor
P: 21,216




#12
Feb2512, 06:46 AM

P: 64




Register to reply 
Related Discussions  
What happens if emitterbase & basecollector junctions are forward biased with 0.7V?  Electrical Engineering  10  
Why the method works? Change a decimal no. from denary(base 10) to octal(base 8)  General Math  1  
Convert base10 212 to base9  Precalculus Mathematics Homework  4  
Base N to Base N Conversion  Linear & Abstract Algebra  1  
AcidBase neutralization w/ more than 1 base.  Chemistry  6 