# Probability current inside the barrier of a finitie square potential well

by StephenD420
Tags: barrier, current, finitie, inside, potential, probability, square
 P: 100 if ψ=C*e^(kx) + D*e^(-kx) show that the probability current density is Jx=(i*k*hbar/m)[c*conj(D) - conj(C)*D] since Jx= (i*hbar/2m)*[ψ * derivative of conj(ψ) - conj(ψ)*derivative of ψ] ψ=C*e^(kx) + D*e^(-kx) conj(ψ)= conj(C)*e^(-kx) + conj(D)*e^(kx) ψ ' = C*k*e^(kx) - D*K*e^(-kx) derivative of conj(ψ) = -conj(C)*k*e^(-kx) + conj(D) *k*e^(kx) plugging in and simplifying I get Jx = (i*hbar/2m)*[-C*conj(C)*k - k*conj(C)*D*e^(-2kx) + C*conj(D)*k*e^(2kx) + D*conj(D)*k -C*conj(C)*k -C*conj(D)*k*e^(2kx) + conj(C)*D*k*e^(-2kx) +D*conj(D)*k] which simplifies to Jx = (i*hbar/2m)*[-2*c*conj(C)*k + 2*D*conj(D)*k] Jx = (i*hbar/m)*[D*conj(D) - C*conj(C)] how do I get from here to Jx=(i*k*hbar/m)[c*conj(D) - conj(C)*D] Thanks so much for any help you guys can provide. I am really stuck as to what to do next. Thanks. Stephen
 P: 100 bump.... Please help me with a nudge to finish this problem up. Thank you for any help you guys can give me. I really appreciate it. Stephen

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