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Gas liquid contact in stripping column

by RAfAEL_SP
Tags: stripping gas water
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RAfAEL_SP
#1
Mar1-12, 04:11 AM
P: 2
[itex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[out][/SUB][/SUB]}[/itex]=[itex]\frac{\sum s^{K}-1}{\sum s^K}[/itex] (1)

for k = 0 to n

Final result:

[itex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[/SUB][/SUB]}[/itex] = [itex]\frac{{S-S^{n+1}}}{1-S^{n+1}}[/itex]

(2)

Does anyone know how to get from (1) to (2).
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tiny-tim
#2
Mar1-12, 04:36 AM
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tiny-tim's Avatar
P: 26,148
Hi RAfAEL_SP! Welcome to PF!

(use _ not SUB in latex, and use tex rather than itex for fractions that ou don;t want to be too tiny! )
Quote Quote by c View Post
[tex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[out][/SUB][/SUB]}[/tex]=[tex]\frac{\sum s^{K}-1}{\sum s^K}[/tex] (1)

for k = 0 to n

Final result:

[itex]\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[/SUB][/SUB]}[/itex] = [itex]\frac{{S-S^{n+1}}}{1-S^{n+1}}[/itex]

(2)

Does anyone know how to get from (1) to (2).
I think you mean [tex]\frac{\sum s^{K-1}}{\sum s^K}[/tex]
Then eg the denominator is (∑sK)/(1 - S)
RAfAEL_SP
#3
Mar1-12, 05:23 AM
P: 2
The exponent is just k


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