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sequence (n,1/n)

 
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Mar2-12, 08:30 AM   #1
 

sequence (n,1/n)


if we have a sequence (n,1/n) , n E N , the sequence converges?

lim n = infinite
lim 1/n = 0

(1,1),(2,1/2),(3,1/3)...(n,1/n)

it is convergent and divergent?!!!
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Mar2-12, 10:35 AM   #2
 
if anybody knows about such a sequence, book or reference, please write here

because i want to learn it

Thank you
Mar2-12, 01:04 PM   #3
 
Quote by zendani View Post
if anybody knows about such a sequence, book or reference, please write here

because i want to learn it

Thank you
In order to converge in R^2, the x-y plane, a sequence of points has to converge in each variable separately. So the sequence (1, 1/n) does not converge.
Mar2-12, 01:07 PM   #4
 
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sequence (n,1/n)


For a sequence of the form (xn,yn) to converge, we require that both xn and yn converges. Here, xn=n, yn=1/n. While yn converges to 0, xn diverges so we say that (n,1/n) diverges.
Mar2-12, 03:39 PM   #5
 
thank you Stevel27 and quasar987, i got it

stevel, i have (n,1/n) no (1,1/n)

so (n, 1/n) diverges and (1,1/n) converges...
Mar2-12, 03:43 PM   #6
 
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correct! :)
Mar2-12, 04:38 PM   #7
 
Quote by zendani View Post
thank you Stevel27 and quasar987, i got it

stevel, i have (n,1/n) no (1,1/n)

so (n, 1/n) diverges and (1,1/n) converges...
Yes, you're right about that. Typo on my part, but of course (1, 1/n) does converge.
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