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Sequence (n,1/n) 
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#1
Mar212, 08:30 AM

P: 15

if we have a sequence (n,1/n) , n E N , the sequence converges?
lim n = infinite lim 1/n = 0 (1,1),(2,1/2),(3,1/3)...(n,1/n) it is convergent and divergent?!!! 


#2
Mar212, 10:35 AM

P: 15

if anybody knows about such a sequence, book or reference, please write here
because i want to learn it Thank you 


#3
Mar212, 01:04 PM

P: 800




#4
Mar212, 01:07 PM

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Sequence (n,1/n)
For a sequence of the form (x_{n},y_{n}) to converge, we require that both x_{n} and y_{n} converges. Here, x_{n}=n, y_{n}=1/n. While y_{n} converges to 0, x_{n} diverges so we say that (n,1/n) diverges.



#5
Mar212, 03:39 PM

P: 15

thank you Stevel27 and quasar987, i got it
stevel, i have (n,1/n) no (1,1/n) so (n, 1/n) diverges and (1,1/n) converges... 


#7
Mar212, 04:38 PM

P: 800




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