Register to reply 
Definition of the derivative to find the derivative of x^(1/3) 
Share this thread: 
#1
Mar812, 11:09 AM

P: 2

1. The problem statement, all variables and given/known data
Use the definition of the derivative to find the derivative of x^(1/3) 2. Relevant equations 3. The attempt at a solution [(x+h)^(1/3)  x^(1/3)]/h I do not know where to go from here. If it were a square root I could conjugate. 


#2
Mar812, 11:26 AM

Emeritus
Sci Advisor
HW Helper
PF Gold
P: 7,800

The difference of cubes can be factored, [itex]a^3b^3=(ab)(a^2+ab+b^2)\,.[/itex] So, suppose you have the difference of cube roots, [itex]\displaystyle P^{1/3}Q^{1/3}[/itex]. In this case, [itex]\displaystyle P^{1/3} = a\,\ \text{ and }\ Q^{1/3} = b\,.[/itex] Multiplying [itex]\displaystyle \left(P^{1/3}Q^{1/3}\right)[/itex] by [itex]\displaystyle \left(P^{2/3}+P^{1/3}Q^{1/3}+Q^{2/3}\right)[/itex] will give [itex]\displaystyle \left(P^{1/3}\right)^3\left(Q^{1/3}\right)^3=PQ\,.[/itex] Thus, [itex]\displaystyle \left(P^{2/3}+P^{1/3}Q^{1/3}+Q^{2/3}\right)[/itex] acts as the "conjugate" for [itex]\displaystyle \left(P^{1/3}Q^{1/3}\right)\,.[/itex] 


#3
Mar812, 01:42 PM

P: 2

oohh...
I would not have thought of that, ever! Thanks a ton. 


Register to reply 
Related Discussions  
Find the derivative of f(x) = (x1)^(2/3) using the definition and then rules.  Calculus & Beyond Homework  1  
Find derivative of floor function using limit definition of derivative?  Calculus & Beyond Homework  10  
Use the definition of derivative to find the derivative of tan(x)  Calculus & Beyond Homework  1  
Definition of Derivative to Find Constants A, B, and C  Calculus & Beyond Homework  0  
Find the derivative, but using the definition thereof  Calculus & Beyond Homework  1 