|Mar10-12, 02:30 AM||#1|
derivation of sagging expression
A bar of length l, breadth b, and depth d when loaded at the centre by a load W sags by
an amount given by
δ = W l^3/(4bd^3Y). Here Y is the young's modulus of the wire. My textbook says that we have to use little calculus to derive this expression. Can you please derive this?
physics news on PhysOrg.com
>> Promising doped zirconia
>> New X-ray method shows how frog embryos could help thwart disease
>> Bringing life into focus
|Mar10-12, 05:13 AM||#2|
Blog Entries: 1
It gets pretty complicated. But take a look at the Wikipedia article "Euler–Bernoulli beam theory", especially the section "Three-point bending" and see if that is any help.
"The shear is constant in absolute value: it is half the central load, P/2. It changes sign in the middle of the beam. The bending moment varies linearly from one end, where it is 0, and the center where its absolute value is PL/4. The deformation of the beam is described by a polynomial of third degree over a half beam (the other half being symmetrical)."
|Similar Threads for: derivation of sagging expression|
|derivation of expression for force||Classical Physics||3|
|Landau's derivation of the Langangian expression||Classical Physics||4|
|Sagging Bottom Quantum Box and Pertubation||Advanced Physics Homework||1|
|The sagging effect and angular speed.||Introductory Physics Homework||1|
|Asteroid Collision Course and Sagging Backpack||Introductory Physics Homework||6|