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Finding limit using l'Hopitals rule 
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#1
Mar2912, 02:26 AM

P: 80

Hello, I am tying to use l'Hopital's rule to solve this limit:
{e^(5+h)e^5} / h limit h tending towards 0 Using l'Hopitals rule I differentiate both numerator and denominator to get: e^(5+h)e^5 / 1 THen plugging 0 back in I get 0/1 which would give me a limit of 0 ? But I think the limit should actually be e^5. Can someone see where I have gone wrong ? Thanks kindly 


#2
Mar2912, 03:06 AM

P: 280




#3
Mar2912, 03:40 AM

P: 80

I dont think I have it right in my attempt above. Any help would be appreciated. Thank you. 


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