I am confused by the design of this AM receiver/tuner circuit.

http://imgur.com/f9n05

I don't understand how the inductor and capacitors on the left design a circuit that resonates at a certain frequency, and I also don't understand why the resistor and capacitor in parallel after the diode create a low-pass filter.

Are the inductor and two capacitors not in parallel with each other? This circuit makes more sense to me if I consider the two capacitors to be in parallel with each other, and in series with the inductor. Then the inductor and capacitors should exhibit resonance at a given frequency and act as a band-pass filter, passing this specific frequency to the rest of the circuit. Is this right?

Can anyone help me out with this circuit?

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 In this circuit it doesn't matter if you consider the two capacitors in parallel are in series or in parallel with the inductor, the effect is the same. Imagine the inductor as a mass that is being moved at a regular frequency by the antenna. The capacitors are like a spring that is alternately compressed and stretched by the oscillating mass. Since the spring keeps the mass oscillating, the antenna only has to supply enough input power to offset the losses due to friction. The oscillation of the mass will increase until the losses equal the power input from the antenna. Likewise in the circuit, the voltage in the inductor-capacitor circuit increases until the losses equal the power supplied by the antenna. If the voltage is high enough, the positive peaks of the oscillation will pass through the diode and charge the capacitor. The 10K resistor allows the capacitor to discharge when the peak of the signal is less than the voltage the capacitor is charged to. In this way the voltage across the final capacitor follows the peak voltage of the signal. When amplified it provides an audio output.

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