
#1
Apr1612, 08:47 AM

P: 14

when we apply kinetic energy conservation...should we split the velocity into two components???
eg))))) two blocks of mass m are connected by a spring and are both given a velocity v at an angle of 45 degree with the horizontal(they lie on the horizontal) ..assuming no friction is present... what will be the maximum elongation of the spring?? i used by equating 1/2 k x2 with the initial ke of the two masses along the horizontal i.e.vcos45???is it correct???pls help me(no vertical motion) 



#2
Apr1612, 09:43 AM

P: 209

Well energy is a scalar so it it's meaningless to split the KE into two components.
You should however find the component of the force that gave the initial velocity in order to find the elongation. 



#3
Apr1612, 10:36 AM

P: 14

can you pls tell me how to to solve it then...or did i do it correctly???




#4
Apr1612, 11:03 AM

P: 209

can any of you guys help to understand kinetic energy???
I'm confused by the problem. How can the velocity be at a 45 degree angle with the horizontal if the masses must move only on the horizontal?




#5
Apr1612, 11:34 AM

P: 14





#6
Apr1612, 12:19 PM

P: 209

In that case, I'd work it as you did.
[itex]2 \frac{1}{2} m (vcos(45°))^{2} = \frac{1}{2}k(Δx)^{2}[/itex] 


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