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Oblique Collisions

by jsmith613
Tags: collisions, oblique
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jsmith613
#1
Apr17-12, 08:02 PM
P: 614
In an oblique collision (when one object hits another object of IDENTICAL mass at a slight angle the two objects move at right angles to each other.

my book says

p2 = p12 + p22

For momenum conservtation:

p= p1+ p2

apparently these equations can only be consistent of the collision occurs at right angles. why?
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haruspex
#2
Apr18-12, 01:46 AM
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These are vectors, right?
p.p = (p1+p2).(p1+p2) [2nd equn]
= p1.p1 + 2.p1.p2 + p2.p2
= p.p + 2.p1.p2 [1st equn]
Hence p1.p2 = 0
jsmith613
#3
Apr18-12, 03:54 AM
P: 614
Quote Quote by haruspex View Post
These are vectors, right?
p.p = (p1+p2).(p1+p2) [2nd equn]
= p1.p1 + 2.p1.p2 + p2.p2
= p.p + 2.p1.p2 [1st equn]
Hence p1.p2 = 0
where has p2.p2 gone in the final line
surely the final line should be
= p1.p2 + p2.p2, no?

haruspex
#4
Apr18-12, 05:25 PM
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Oblique Collisions

1st equn says p.p = p1.p1 + p2.p2
To get from my second line to my third line, use this to substitute p.p for p1.p1 + p2.p2.


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