
#1
Apr1712, 08:02 PM

P: 614

In an oblique collision (when one object hits another object of IDENTICAL mass at a slight angle the two objects move at right angles to each other.
my book says p^{2} = p_{1}^{2} + p_{2}^{2} For momenum conservtation: p= p_{1}+ p_{2} apparently these equations can only be consistent of the collision occurs at right angles. why? 



#2
Apr1812, 01:46 AM

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These are vectors, right?
p.p = (p1+p2).(p1+p2) [2nd equn] = p1.p1 + 2.p1.p2 + p2.p2 = p.p + 2.p1.p2 [1st equn] Hence p1.p2 = 0 



#3
Apr1812, 03:54 AM

P: 614

surely the final line should be = p1.p2 + p2.p2, no? 



#4
Apr1812, 05:25 PM

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P: 9,205

Oblique Collisions
1st equn says p.p = p1.p1 + p2.p2
To get from my second line to my third line, use this to substitute p.p for p1.p1 + p2.p2. 


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