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Intro Electromag Question - Wave Equation |
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| Apr17-12, 09:54 PM | #1 |
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Intro Electromag Question - Wave Equation
1. The problem statement, all variables and given/known data
![]() 2. Relevant equations ![]() 3. The attempt at a solution b) I could figure it out if kz was changed to kx... Double Derivative of E(r, t) with respect to x is = 0 Double Derivative of E(r, t) with respect to t is = -ω2*E0*cos(kz - wt + ∅0) Multiply the second term by k2/ω2 doesn't help. |
| Apr18-12, 09:13 PM | #2 |
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The 'x' in the [tex] \frac{\partial^2 \psi}{\partial x^2} - \frac{1}{c^2} \frac{\partial^2 \psi}{\partial t^2} = 0 [/tex] wave equation simply refers to the spacial dimension (instead of time dimension). The wave equation doesn't imply that all waves *must* travel in the North-South direction only and that East-West and Up-Down directions are prohibited. It just means "spacial". That's because the version of the wave equation that you gave is the "one dimensional" wave equation. For a three denominational version, use this version of the wave equation: [tex] \nabla^2 \psi - \frac{1}{c^2} \frac{\partial^2 \psi}{\partial t^2} = 0 [/tex] where [itex] \nabla^2 [/itex] is the Laplacian operator. In Cartesian coordinates, the Laplacian is [tex] \nabla^2 = \frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial y^2} + \frac{\partial^2}{\partial z^2} [/tex] --------------- Edit: It doesn't matter much for this particular problem, but I couldn't tell if the (1,0,0) notation was Cartesian (x,y,z) or cylindrical (r,θ,z). In cylindrical coordinates, the Laplacian of a function, f is [tex] \nabla^2 f = \frac{1}{r} \frac{\partial}{\partial r} \left(r \frac{\partial f}{\partial r} \right) + \frac{1}{r^2}\frac{\partial^2 f}{\partial \theta^2} + \frac{\partial^2 f}{\partial z^2} [/tex] |
| Apr19-12, 02:30 AM | #3 |
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Hey thank you so much for this, it certainly makes a lot more sense with the three-d wave equation!
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| electrodynamics, equation, maxwell, solve, wave |
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