# Turing machine - polynomial time expression

by xeon123
Tags: expression, machine, polynomial, time, turing
 P: 81 In the Turing Machine, the machine accepts a word if the computation terminates in the accepting state. The language accepted by the machine, L(M), has associated an alphabet Δ and is defined by L(M) = {w $\in$ $\Delta$} This means that the machine understands the word w if w belongs to the language. We denote by Tm(w) the number of steps in the computation of M on the input w. If the computation never halts, then Tm(w)=infinity. Also, we denote the worst case run time of M as Tm(n) = max{Tm(w)} which means the biggest words in the dictionary (I suppose). But, we say that M runs in polynomial time if there exists k such that for all n, T(n)$\leq$ n^k + k. I don't understand what n^k+k means. Can anyone explain me the last expression? Thanks,
 Quote by xeon123 In the Turing Machine, the machine accepts a word if the computation terminates in the accepting state. The language accepted by the machine, L(M), has associated an alphabet Δ and is defined by L(M) = {w $\in$ $\Delta$} This means that the machine understands the word w if w belongs to the language. We denote by Tm(w) the number of steps in the computation of M on the input w. If the computation never halts, then Tm(w)=infinity. Also, we denote the worst case run time of M as Tm(n) = max{Tm(w)} which means the biggest words in the dictionary (I suppose). But, we say that M runs in polynomial time if there exists k such that for all n, T(n)$\leq$ n^k + k. I don't understand what n^k+k means. Can anyone explain me the last expression? Thanks,