|Apr28-12, 03:42 PM||#1|
The problem statement, all variables and given/known data
Given that the real and imaginary parts of the complex number [itex]z=x+iy[/itex] satisfy the equation [itex](2-i)x-(1+3i)y=7[/itex]. Find x and y.
The attempt at a solution
I know it's quite simple. Just equate the real and imaginary parts, but i checked and redid it again, but the answer still evades me!
[tex](2x-y-7) + i(-x-3y)=0
I replaced in the original equation but i can't get 7 on the L.H.S.
The correct answers: x=3 and y=-1.
|Apr28-12, 04:48 PM||#3|
[itex]2x-y-7=x[/itex]you are saying that
[itex](2x-y-7) + i(-x-3y)=z\ .[/itex]That's not what you're trying to solve !
|Apr28-12, 08:27 PM||#4|
I was confused about z=x+iy. I thought i had to compare the real and imaginary parts of z with those of the equation in order to solve it. I now realize that it has absolutely nothing to do with z. All i had to do was solve the equation independently and ignore whatever was given for z.
\\-x-3y=0[/tex]I get the correct answers.
Thank you, LCKurtz and SammyS.
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