
#1
Apr2812, 05:24 PM

P: 7

Hey,
I was going through some mechanics notes and came across this quadratic equation to solve for x. In my notes it is supposed to equal 3 however I do not get that result. I am not sure if I am simplifying it wrong or what. I am ending up with 2.12 for the positive value. Please let me know if you get 3 or 2.12 so that I know if the error is in my calculations or in my notes. Thanks in advanced. 



#2
Apr2812, 05:39 PM

P: 606

It must be some mistake in your notes: if you put [itex]x=3[/itex] in the given eq., one gets that the LHS is not an integer whereas the RHS is... DonAntonio 



#4
Apr2912, 02:36 AM

P: 16

Quadratic Equation help
3 is correct if the LHS is amended to contain 144x^{2} rather than 144 + x^{2}.




#5
Apr2912, 06:29 PM

P: 4

um... I haven't done this in a while so forgive me for being simple.... but that's not an equation.
if you put x=10 you end up with the equation 122=900, which isn't true. There's been some kind of mistake. 



#6
Apr2912, 09:22 PM

P: 606

No, that is too an equation. To solve it means to find out the numerical values of x that when substituted in the equation give a true equality. What you've shown above is that the numerical value x = 10 is not (one of the) a solution(s) of the equation. DonAntonio 



#7
Apr2912, 09:33 PM

P: 4

oh, ok, yes. Sorry engineering maths was a decade ago for me. It's amazing how quickly the knowledge vanishes.
I reduced the original equation down to 0=71.5x^2+900x2628 and got 0=(x4.604)*(x7.984) 


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