Flexibility 2

Yh Hoo

1 = √(1)
= √(-1)(-1)
= (√-1)(√-1)
= i.i
= i[itex]^{2}[/itex]
= -1
Is this a correct equation??
anythings wrong with this?
i think theoretically it is correct but it seems like
√(1) = √(-1)(-1)
√(1) = √(1)(1) also!!
so how to explain this??

*DonAntonio*

Quote by Yh Hoo

1 = √(1)
= √(-1)(-1)
= (√-1)(√-1)
= i.i
= i[itex]^{2}[/itex]
= -1
Is this a correct equation??
anythings wrong with this?
i think theoretically it is correct but it seems like
√(1) = √(-1)(-1)
√(1) = √(1)(1) also!!
so how to explain this??

Squaring is a double branched complex variable function, and thus "usual" properties in real numbers can fail miserably.

In this case the problem appears in the third equality: it isn't true without imposing certain restrictive conditions.

DonAntonio

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Yh Hoo	Flexibility 2 Tweet 1 = √(1) = √(-1)(-1) = (√-1)(√-1) = i.i = i[itex]^{2}[/itex] = -1 Is this a correct equation?? anythings wrong with this? i think theoretically it is correct but it seems like √(1) = √(-1)(-1) √(1) = √(1)(1) also!! so how to explain this??