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Flexibility 2

by Yh Hoo
Tags: flexibility
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Yh Hoo
#1
May3-12, 11:56 AM
P: 73
1 = √(1)
= √(-1)(-1)
= (√-1)(√-1)
= i.i
= i[itex]^{2}[/itex]
= -1
Is this a correct equation??
anythings wrong with this?
i think theoretically it is correct but it seems like
√(1) = √(-1)(-1)
√(1) = √(1)(1) also!!
so how to explain this??
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DonAntonio
#2
May3-12, 12:10 PM
P: 606
Quote Quote by Yh Hoo View Post
1 = √(1)
= √(-1)(-1)
= (√-1)(√-1)
= i.i
= i[itex]^{2}[/itex]
= -1
Is this a correct equation??
anythings wrong with this?
i think theoretically it is correct but it seems like
√(1) = √(-1)(-1)
√(1) = √(1)(1) also!!
so how to explain this??


Squaring is a double branched complex variable function, and thus "usual" properties in real numbers can fail miserably.

In this case the problem appears in the third equality: it isn't true without imposing certain restrictive conditions.

DonAntonio


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