# Flexibility 2

by Yh Hoo
Tags: flexibility
 P: 73 1 = √(1) = √(-1)(-1) = (√-1)(√-1) = i.i = i$^{2}$ = -1 Is this a correct equation?? anythings wrong with this? i think theoretically it is correct but it seems like √(1) = √(-1)(-1) √(1) = √(1)(1) also!! so how to explain this??
P: 606
 Quote by Yh Hoo 1 = √(1) = √(-1)(-1) = (√-1)(√-1) = i.i = i$^{2}$ = -1 Is this a correct equation?? anythings wrong with this? i think theoretically it is correct but it seems like √(1) = √(-1)(-1) √(1) = √(1)(1) also!! so how to explain this??

Squaring is a double branched complex variable function, and thus "usual" properties in real numbers can fail miserably.

In this case the problem appears in the third equality: it isn't true without imposing certain restrictive conditions.

DonAntonio

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