Register to reply 
Flexibility 2by Yh Hoo
Tags: flexibility 
Share this thread: 
#1
May312, 11:56 AM

P: 73

1 = √(1)
= √(1)(1) = (√1)(√1) = i.i = i[itex]^{2}[/itex] = 1 Is this a correct equation?? anythings wrong with this? i think theoretically it is correct but it seems like √(1) = √(1)(1) √(1) = √(1)(1) also!! so how to explain this?? 


#2
May312, 12:10 PM

P: 606

Squaring is a double branched complex variable function, and thus "usual" properties in real numbers can fail miserably. In this case the problem appears in the third equality: it isn't true without imposing certain restrictive conditions. DonAntonio 


Register to reply 
Related Discussions  
Flexibility  multiple methods for solutions?  General Math  5  
Civil Engineering  Matrix Flexibility Method  Engineering, Comp Sci, & Technology Homework  0  
Flexibility Matrix  Mechanical Engineering  3  
Flexibility Method question  General Engineering  0  
Kevlar flexibility  Biology, Chemistry & Other Homework  2 