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Oscillations and Gravity 
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#1
May812, 12:37 AM

P: 2

On the planet Newtonia, a simple pendulum having a bob with mass 1.00 and a length of 195.0 takes 1.40 , when released from rest, to swing through an angle of 12.5 , where it again has zero speed. The circumference of Newtonia is measured to be 51400 .
I solved for g using T = 2pi*sqrt(L/g) and then i used this g plus the constant G and the radius solved from the given circumference to calculate the mass of the planet from the equation g = GM/R^2 but can't get the answer, i don't know if its because I'm not taking the angle into account? 


#2
May812, 07:00 AM

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P: 26,148

hi pdiddy94! welcome to pf!
but the period T is for two swings, isn't it? 


#3
May812, 10:52 AM

P: 2

ohh, thank you that makes sense



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