Oscillations and Gravity


by pdiddy94
Tags: gravity, oscillations
pdiddy94
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#1
May8-12, 12:37 AM
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On the planet Newtonia, a simple pendulum having a bob with mass 1.00 and a length of 195.0 takes 1.40 , when released from rest, to swing through an angle of 12.5 , where it again has zero speed. The circumference of Newtonia is measured to be 51400 .

I solved for g using T = 2pi*sqrt(L/g) and then i used this g plus the constant G and the radius solved from the given circumference to calculate the mass of the planet from the equation g = GM/R^2 but can't get the answer, i don't know if its because I'm not taking the angle into account?
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tiny-tim
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#2
May8-12, 07:00 AM
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hi pdiddy94! welcome to pf!
Quote Quote by pdiddy94 View Post
takes 1.40 , when released from rest, to swing through an angle of 12.5 , where it again has zero speed.

i don't know if its because I'm not taking the angle into account?
the angle makes no difference (so long as it's reasonably small, as 12.5 is),

but the period T is for two swings, isn't it?
pdiddy94
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#3
May8-12, 10:52 AM
P: 2
ohh, thank you that makes sense


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