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Complex conjugate of a derivative wrt z

 
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May11-12, 12:08 PM   #1
 

Complex conjugate of a derivative wrt z


First post!

Is it true that for a complex function f([itex]{z}[/itex],[itex]\overline{z}[/itex])

[itex]\overline{\frac{∂f}{∂z}}[/itex] =[itex]\frac{∂\overline{f}}{∂\overline{z}}[/itex]

I think I proved this while trying to solve a problem. If it turns out it's not true and I've made a mistake, I'll upload my 'proof' and have the mistakes pointed out :)

Thanks
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May11-12, 01:32 PM   #2
 
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hi stallm!welcome to pf!

but if f(z,z*) = z* then ∂f/∂z = 0
May11-12, 01:52 PM   #3
 
Quote by tiny-tim View Post
hi stallm!welcome to pf!

but if f(z,z*) = z* then ∂f/∂z = 0
That would be alright, because f*=z, so ∂(f*)/∂(z*) =0, so the formula works for this function
May11-12, 02:00 PM   #4
 
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Complex conjugate of a derivative wrt z


ah, i misread it
in that case, yes …

it's f(x,y), you're swapping x and y, differentiating wrt x instead of y, and swapping back again (for ∂f/∂z = (∂f*/∂z*)*)
May11-12, 02:08 PM   #5
 
Thank you!
May12-12, 07:54 AM   #6
 
Quote by stallm View Post
First post!

Is it true that for a complex function f([itex]{z}[/itex],[itex]\overline{z}[/itex])

[itex]\overline{\frac{∂f}{∂z}}[/itex] =[itex]\frac{∂\overline{f}}{∂\overline{z}}[/itex]

I think I proved this while trying to solve a problem. If it turns out it's not true and I've made a mistake, I'll upload my 'proof' and have the mistakes pointed out :)

Thanks
I do not think this is correct.
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