Complex conjugate of a derivative wrt z

First post!

Is it true that for a complex function f(${z}$,$\overline{z}$)

$\overline{\frac{∂f}{∂z}}$ =$\frac{∂\overline{f}}{∂\overline{z}}$

I think I proved this while trying to solve a problem. If it turns out it's not true and I've made a mistake, I'll upload my 'proof' and have the mistakes pointed out :)

Thanks
 PhysOrg.com science news on PhysOrg.com >> New language discovery reveals linguistic insights>> US official: Solar plane to help ground energy use (Update)>> Four microphones, computer algorithm enough to produce 3-D model of simple, convex room
 Blog Entries: 27 Recognitions: Gold Member Homework Help Science Advisor hi stallm!welcome to pf! but if f(z,z*) = z* then ∂f/∂z = 0

 Quote by tiny-tim hi stallm!welcome to pf! but if f(z,z*) = z* then ∂f/∂z = 0
That would be alright, because f*=z, so ∂(f*)/∂(z*) =0, so the formula works for this function

Blog Entries: 27
Recognitions:
Gold Member
Homework Help
Science Advisor

Complex conjugate of a derivative wrt z

ah, i misread it
in that case, yes …

it's f(x,y), you're swapping x and y, differentiating wrt x instead of y, and swapping back again (for ∂f/∂z = (∂f*/∂z*)*)
 Thank you!

 Quote by stallm First post! Is it true that for a complex function f(${z}$,$\overline{z}$) $\overline{\frac{∂f}{∂z}}$ =$\frac{∂\overline{f}}{∂\overline{z}}$ I think I proved this while trying to solve a problem. If it turns out it's not true and I've made a mistake, I'll upload my 'proof' and have the mistakes pointed out :) Thanks
I do not think this is correct.

 Similar discussions for: Complex conjugate of a derivative wrt z Thread Forum Replies Calculus 1 Calculus 8 Calculus 2 Calculus & Beyond Homework 2 Calculus 5