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How do you find all the values of "a" such that f is continuous on all real numbers? |
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| May15-12, 08:09 PM | #1 |
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How do you find all the values of "a" such that f is continuous on all real numbers?
Find all values of a such that f is continuous on [itex]\Re[/itex]
f(x)= x+1 if x[itex]\leq[/itex] a x^2 if x>a I tried solving but i do not even know where to start! Please help! |
| May15-12, 08:17 PM | #2 |
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We know (or you should know!) that x+1 and x^2 are continuous functions because they are polynomials. When you create a continuous piece-wise function, ##f(x)##, you want ##f(a)## to be continuous. This means ##\displaystyle \lim_{x \to a^-} f(a) = \lim_{x \to a^+} f(a) = f(a)##
You can think of it in lay man's terms as choosing values of a so that you can graph the function without lifting your pencil at ##f(a)##. |
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| calculus, continuity, limits, piecewise, values |
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