Tricky Questions!!!

I like Serena

Nice!

micromass

OK, I'm very bored right now, so I'm going to be pedantic.

The cannibals say "if you say a lie, we'll eat you slowly. if you say a truth, we'll eat you fast."

But they did not say what they would do if you tell them a self-contradicting statement. If this trick should work, then the cannibals should have said: "we'll eat you slowly if and only if you tell a lie. we'll eat you fast, if and only if you speak the truth."

Reminds me of

I like Serena

What if the cannibals were lying?

davee123

Of course, I would argue the comic is incorrect-- the "tester" says "Tom Smith has just died as a result of your decision", but that's wrong. Tom Smith didn't die as a result of the subject's decision. He died as a result of the tester's decision. Should've just said "Tom Smith has just died". If someone was going to die regardless of whether or not the button was pushed, then that's not a decision that's up to the subject.

DaveE

Jimmy Snyder

Everything the tester said was true. However. there are two things the tester failed to mention. One was that if you don't push the button Tom Smith will be killed and someone somewhere in the world will receive one million dollars. The other thing she left out was that if you do push the button the someone who will be killed will not be Tom Smith.

evra

You saw a shirt for 97DOLLARS.
You didn't have the cash so you borowed 50DOLLARS from you dad and 50DOLLARS from your mum.
50+50=100DOLLARS
you bought the shirt and had 3 dollars change.

you gave you mum 1DOLLAR, 1DOLLAR to your dad and you kept 1DOLLAR to yourself.

now you owe your mum 49DOLLARS and your dad 49DOLLARS.

49DOLLARS + 49DOLLARS = 98DOLLARS + your 1DOLLAR = 99DOLLARS.

Where is the missing 1DOLLAR?????????????

evra

is it that no one can do the above????

collinsmark

sahil_dev

nothing..coz it's just a hole...

jessy246

4100

jessy246

Lions because they would be dead by that point and i would get to eat them for food and also wear the fur/skin for warmth if it gets cold.

evra

six monkeys are each pregnant with 7 kids ,a hunter is running after these monkeys shooting them with a gun at an intervals, the speed of the bullets are constant and are twice less than the speed of the fastest monkey, if the monkeys are running with a constant speed, in such a way that the fastest monkey is twice the second, the second is twice the third etc. at that limit, how many monkeys can the hunter kill, how many will survive and how many kids probably they might deliver?

evra

So no one is able to answer this one or is it that this threat is closed?

Evo

Collinsmark explained your error.

Jimmy Snyder

Let's assume that the bullet is like a cartoon bullet. That is, it follows the path of the victim. This is different from the way a heat seaking missile would work. When the target makes a right turn, the heat seeking missile would immediately turn as well so that it was always pointed directly at the target. However, a cartoon bullet would continue in a straight path toward the point where the victim turned. Then it might make a right turn and follow the victim, or it might slow down to a halt, shade its eyes and look for the victim and then make the right turn. We will assume that our cartoon bullets don't do that, but just follow the path of the victim. Let's also assume that the bullet will always chase after the mother, not the offspring.

Let's say that it takes x minutes to throw a litter and that the monkey has a lead time of y minutes before the bullet strikes. The monkey that runs faster than the bullet can throw her litter and survive since she can always run until y becomes greater than x. Once that happens, she can stop, throw her litter, get up and start running again and never get caught.

The monkey that runs as fast as the bullet never needs to be killed by it. However, if x is greater than y, she can never throw her litter as she will die before she finishes. Perhaps some offspring will survive, but not necessarily all of them. However, if x is less than y, then there is no problem. She stops, throws her litter, gets up and starts running again and never gets caught.

The monkey that runs slower than the bullet is in a similar situation as the monkey that runs as fast as the bullet. If x is greater than y, she cannot be sure of delivering her litter, but if x is less than y she can. The difference is that no matter whether she delivers or not, she will be killed by the bullet.

The problem is ill posed since we are not told whether x is greater than y. What's worse, if we are told, then the problem is trivial.