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How do I explicate "A is countable"? |
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| May24-12, 01:51 AM | #1 |
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How do I explicate "A is countable"?
My attempt:
In set theory, every thing is a set, even functions. Thus when we say "A is countable in M" we mean that there is another set B in M that contains {naturals} and A as ordered pairs. I'm having trouble spelling out the "as ordered pairs" part. Is is: B in M that contains N and A in ordered pairs such that (a, n) where a ∈ A and n ∈ N and for every a there is exactly one corresponding n and for every n there is exactly one corresponding a? Is there an easier way to write this? |
| May24-12, 08:41 AM | #2 |
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When you say "A is countable in M", you mean A is a countable subset of M, right?
Okay then that means that there is a bijection between A and N. So there exists a set of ordered pairs {(a,n) | a belongs to A and n belongs to N}. For each a in A there is exactly one corresponding ordered pair whose first component is a (this makes it a function), and likewise for each n in N (which makes it bijective). This set corresponding to the bijection is itself a subset of the Cartesian product M X N. If you want to break this down one step further then (a,n) = { {a},{a,n}}. So the ordered pairs are technically subsets of the power set of (M union N). |
| May24-12, 12:32 PM | #3 |
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