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Various RLC Circuit Problems (Resonance Frequency, Phase, Current) |
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| Jun10-12, 06:45 PM | #1 |
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Various RLC Circuit Problems (Resonance Frequency, Phase, Current)
1. The problem statement, all variables and given/known data
An RLC circuit has L = 20mH, R = 20kΩ, C = 250μF. 1) Calculate the resonance frequency for this circuit. 2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance. 3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time. 4) Draw the phasor diagram for t=0 seconds. 2. Relevant equations ω[itex]_{o} = \frac{1}{\sqrt{LC}}[/itex] ϕ = tan[itex]^{-1} \left[\frac{X_{L}-X_{C}}{R}\right][/itex] [itex]X_{L}[/itex] = ωL [itex]X_{C} = \frac{1}{ωC}[/itex] Z = [itex]\sqrt{R^{2} + (X_{L} - X_{C})^{2}}[/itex] I(t) = [itex]\frac{ε}{Z}[/itex] 3. The attempt at a solution So I wasn't sure if I was doing any of this correctly; with all of the formulas/equations, it looked like the questions were mostly some simple plug-in questions, but I feel like my numbers just weren't coming out quite right. 1) Calculate the resonance frequency for this circuit. ω[itex]_{o} = \frac{1}{\sqrt{LC}}[/itex] L = 20mH = 0.02H; C = 250μF ω[itex]_{o} = \frac{1}{\sqrt{(0.02H)(250μF)}} = \frac{1}{2.24 sec}[/itex] = 0.447 Hz 2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance. Phase Angle ϕ = tan[itex]^{-1} \left[\frac{X_{L}-X_{C}}{R}\right][/itex] [itex]X_{L} = ωL = (400)(0.02) =[/itex] 8 [itex]X_{C} = \frac{1}{(400)(250)} = \frac{1}{100,000} =[/itex] 0.00001 R = 20kΩ ϕ = tan[itex]^{-1} \left[\frac{X_{L}-X_{C}}{R}\right] = tan^{-1} \left[\frac{8-0.00001}{20,000}\right] = tan^{-1} \left[\frac{7.99999}{20,000}\right] = tan^{-1} \left[3.99x10^{-4}\right] =[/itex] 0.0229° Impedance Z = [itex]\sqrt{R^{2} + (X_{L} - X_{C})^{2}} = \sqrt{20,000^{2} + (8 - 0.00001)^{2}} = \sqrt{4.0x10^{8} + 63.99} =[/itex] 20000.0016Ω 3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time. I(t) = [itex]\frac{ε}{Z} = \frac{30[V]sin(400[rad/s]t)}{20000.0016[Ω]} = \frac{30[V]sin(400[rad/s]t)}{20000.0016[Ω]} = 0.00149sin(400t)[/itex] So I(t) = 0.00149sin(400t) 4) Draw the phasor diagram for t=0 seconds. I wasn't sure at all how to go about doing this one. As far as I can tell, this one ends up being a graph with voltage and current functions (current found in #3) drawn at t=0, showing how out of phase they are at that time, although I'm not sure how to find the voltage/what to use to find it. Of course, I don't want anyone to draw the graph for me, but some advice on phasor diagrams in general/a push in the right direction would be very nice. Any help would be greatly appreciated. Thank you in advance! |
| Jun10-12, 11:11 PM | #2 |
Recognitions:
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The capacitance is given in microfarads: C=250 *10-6 F. Repeat the calculations.
ehild |
| Jun10-12, 11:49 PM | #3 |
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Alrighty. I guess my mind totally drew a blank around that capacitance.
![]() I feel a lot better about the frequency now; I'm hoping the others are okay, too. 1) Calculate the resonance frequency for this circuit. ω[itex]_{o} = \frac{1}{\sqrt{LC}}[/itex] L = 20mH = 0.02H; C = 250x10^{-6}F ω[itex]_{o} = \frac{1}{\sqrt{(0.02H)(250x10^{-6}F)}} = \frac{1}{.00223 sec}[/itex] = 447.21 Hz 2) For a frequency ω=400 rad/s, determine the phase angle and the circuit impedance. Phase Angle ϕ = tan[itex]^{-1} \left[\frac{X_{L}-X_{C}}{R}\right][/itex] [itex]X_{L} = ωL = (400)(0.02) =[/itex] 8 [itex]X_{C} = \frac{1}{(400)(250x10^{-6})} = \frac{1}{.1} =[/itex] 10 R = 20kΩ ϕ = tan[itex]^{-1} \left[\frac{X_{L}-X_{C}}{R}\right] = tan^{-1} \left[\frac{8-10}{20,000}\right] = tan^{-1} \left[\frac{-2}{20,000}\right] = tan^{-1} \left[-1.0x10^{-4}\right] =[/itex] -0.0057° Impedance Z = [itex]\sqrt{R^{2} + (X_{L} - X_{C})^{2}} = \sqrt{20,000^{2} + (8 - 10)^{2}} = \sqrt{4.0x10^{8} + 4} =[/itex] 20000.0001Ω 3) Using ε = 30[V]sin(ωt), calculate the current in the circuit. This will be a function of time. I(t) = [itex]\frac{ε}{Z} = \frac{30[V]sin(400[rad/s]t)}{20000.0001[Ω]} = \frac{30[V]sin(400[rad/s]t)}{20000.0001[Ω]} = 0.0015sin(400t)[/itex] So I(t) = 0.0015sin(400t) 4) Draw the phasor diagram for t=0 seconds. I'm still a little confused about this phasor diagram, but I think I can get by. Again, if anyone could offer a little advice on this, it would be great. And thank you for catching my mistake, ehild. |
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