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Definite integral of exp and error function |
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| Jun11-12, 06:03 AM | #1 |
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Definite integral of exp and error function
Hi,
I've been trying to evaluate the following integral [tex] \int_{z}^{\infty}\exp\left(-y^{2}\right)\mathrm{erf}\left(b\left(y-c\right)\right)\,\mathrm{d}y [/tex] or equivalently [tex] \int_{z}^{\infty}\exp\left(-y^{2}\right)\mathrm{erfc}\left(b\left(y-c\right)\right)\,\mathrm{d}y [/tex] [tex]\mathrm{erf}\left(x\right)=\frac{2}{\sqrt{\pi}} \int_{0}^{x}\exp\left(-u^{2}\right)\,\mathrm{d}u, \quad\quad \mathrm{erfc}\left(x\right)=1-\mathrm{erf}\left(x\right)=\frac{2}{\sqrt{\pi}} \int_{x}^{+\infty}\exp\left(-u^{2}\right)\,\mathrm{d}u[/tex] I guess I tried to employ all techniques I'm familiar with but with no result. Can anyone help me with this one, please? Thank you! |
| Jun11-12, 02:42 PM | #2 |
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Recognitions:
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To the best of my knowledge, it can't be done analytically. I suggest you start with the erf representation and see if the two exponentials might be combined into one, so that you might have an erf for the integral.
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| Jun15-12, 06:27 AM | #3 |
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Thanks mathman for your reply. I guess I'm not able to deal with this integral. I have a question though. I'm not a mathematician nor a math student so I was wondering if anyone could explain to me why the integral
[tex]\int_{-\infty}^{\infty}\exp\left(-y^{2}\right) \mathrm{erf}\left(b\left(y-c\right)\right)\,\mathrm{d}y=-\sqrt{\pi}\,\mathrm{erf}\left(\frac{bc}{\sqrt{1+b^{2}}}\right)[/tex] can be evaluated quite easily (using differentiation under integral sign method) and the integral from my original post seems to have no analytical solution? Thanks! |
| Jun15-12, 03:51 PM | #4 |
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Recognitions:
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Definite integral of exp and error function
I haven't looked at it in detail, but it looks like the problem is analogous to integrating the Gaussian. When you integrate over the entire real line you get a neat analytic solution, but integrating over part of the line ends up with erf.
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| Jun15-12, 04:04 PM | #5 |
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Ok, I guess I know what you mean. Thanks again!
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| Jun16-12, 03:42 AM | #6 |
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Hi !
in attachment, a method for solving the definite integral. |
| Jun17-12, 05:02 AM | #7 |
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Hi JJacquelin! Your post helped me with showing that the constant of integration [tex]C=0[/tex] in a more general formula:
[tex] \int_{-\infty}^{\infty}\exp\left(-b^{2}(x-c)^{2}\right)\mathrm{erf}\left(a\left(x-d\right)\right)\,\mathrm{d}x=\frac{\sqrt{\pi}}{b} \mathrm{erf}\left(\frac{ab\left(c-d\right)}{\sqrt{a{}^{2}+b{}^{2}}}\right),\quad b>0 [/tex] Thank you! |
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