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Gravitational Potential Energy |
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| Jul5-12, 01:19 PM | #1 |
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Gravitational Potential Energy
Is what I am currently reading about. The book I am reading presents it by giving an example; it proposes lifting a mass without any acceleration through a height, h, with an upward force equal and opposite to its weight. Does that mean the net work done on this mass is zero? My hand still does work on the mass as well as gravity, but the amount of work does is zero, right?
Also, where does the mass get its potential energy from? I know its position contributes to its potential energy, but what about the energy I use to to lift it up? Does the energy I use transfer and convert into potential energy as I lift the mass up? |
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| Jul5-12, 01:35 PM | #2 |
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F=m*a so if the forces sum to zero the acceleration is zero but the velocity need not be zero. If the velocity is non zero then the lifting device expends energy.. Work = F*h The power is the rate of doing work so.. Power = F*h/t where t is the time taken to move h and h/t is the vertical velocity |
| Jul5-12, 01:46 PM | #3 |
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It might help to understand this point... In theory if you hold a weight at a constant height you do no work on it. Consider a book shelf. It needs no power source to hold the books at a constant height. In practice the human body isn't very efficient. Your body burns energy just creating a force even if it's doing no work. So it feels like you are doing work holding up a weight at a constant height but you don't actually do work on the weight until you raise it higher. |
| Jul5-12, 06:22 PM | #4 |
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Gravitational Potential Energy
How can there be a net work if there is no change in velocity and, presumably, the mass remains the same?
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| Jul5-12, 07:17 PM | #5 |
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Applying a force that raises the object does work, even if no acceleration is done. (After the initial acceleration of course) |
| Jul5-12, 07:35 PM | #6 |
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| Jul5-12, 07:38 PM | #7 |
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| Jul6-12, 04:27 AM | #8 |
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| Jul7-12, 07:17 AM | #9 |
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| Jul7-12, 07:27 AM | #10 |
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But if you think of gravity as being represented by a potential energy term, then you can think of the work you do as becoming gravitational potential energy. Work done by all forces (including gravity) = ΔKE Work done by all forces (except gravity) = ΔKE + ΔPE These two formulations of the Work-Energy theorem are equivalent. In the second version, work done by gravity is already included in the PE term. |
| Jul7-12, 07:41 AM | #11 |
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So, gravitational potential energy is more a less an accounting system to measure the potential work that could be done due to the objects position. And so this gravitational potential energy doesn't actually become "real" unto the object starts falling? which we have an account of the energy it possess the the potential work it could do
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| Jul7-12, 09:01 AM | #13 |
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Thank you all for you help.
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