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Can a magnetic fields/forces do work on a current carrying wire?! |
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| Jul19-12, 09:18 PM | #35 |
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Can a magnetic fields/forces do work on a current carrying wire?!Could you clarify this a bit more(Simpler way), I do understand the "tethered" part. But not sure what you're talking about hee... E forces... Whats SN forces? I thought by applying the magnetic force on the electron directly, an indirect force is applied on the proton and neutron? |
| Jul19-12, 09:19 PM | #36 |
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| Jul20-12, 07:58 AM | #37 |
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Have I helped? BR. Claude |
| Jul20-12, 12:24 PM | #38 |
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In a sense they are... So as E force, So as the N force. They all were triggered in this even or "action" to do work. I would say this in a general simpler way: Magnetic force can do work with the presence of E,force + N,force. Electric force can do work with the presence of M,force + N,force. N force can do work with the presence of M,force + E,force. In a sense the motor effect... A simple effect CAN NEVER occur without the upper 3 rules. They are all dependent on each other. without one of them. Nothing would happen. Simple forces added up together to give the total work. |
| Jul20-12, 02:32 PM | #39 |
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In a motor, of course all 3 forces work in unison, but it is safe to say that the magnetic forces, i.e. B/H, are the quantities that literally control the motor action. SNF & E tag along like an obedient shadow, but magnetic is in charge. Using my 3 ball analogy, a magnet lifts 3 tethered balls, steel, wood, & rubber. The magnet cannot lift wood and/or rubber, but it lifts them indirectly by lifting the steel ball directly, & relying on the E & SN tether forces to lift the rubber & wood balls. But let us not forget, the magnet must provide a lifting force equal to the combined weight of all 3 balls. If each ball weighs a pound force, then the mag force must be 3 lbf. But the E & SN forces are only equal to the weight they carry. If the steel ball is on top, then E & SN provide 2 lbf, while the mag is 3 lbf. So the magnetic force is definitely the prime mover but it still relies on help from E & SN. Interesting question. These puzzles get us thinking. I want to thank everybody here for being polite. These types of questions usually end up in a mud wrestling match. Everybody on this thread conducted themselves very well, & I take my hat off to all. I hope future discussions can be this civil. Best regards. Claude |
| Jul20-12, 02:49 PM | #40 |
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I think the following is valid, but demonstrating it may sometimes be difficult. ONLY in the presence of both E forces + N forces+gravitational forces can magnetic fields do work on an electric charge or electric current. |
| Jul20-12, 03:53 PM | #41 |
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Thanks again to all. BR. Claude |
| Jul21-12, 12:51 AM | #42 |
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I believe then the E force + SN force would interact with the M forces. We all should break down the concept of Work in, and Work out. Its more understanding when you would say the Forces in and the Netforce out. If you see where I'm going with this... It simply draws a better picture you can visualize it and understand everything more clearly then saying energy In and the energy converted(With respect to all laws, thats just my own way of understanding the relationship of energy,work,force all together). |
| Jul21-12, 12:54 AM | #43 |
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Thank you all again for you're efforts!
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| Jul21-12, 06:39 AM | #44 |
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It is important to note that magnetic fields apply forces only on moving charged particles, and for example in the the case of the electric motor, not on the wire itself but on the electrons.
I found this picture from google: ![]() Consider a stationary particle that is on the path of the moving charged particle after it has moved through the magnetic field (for example where the arrow points that is with the text "Path of the particle"). The charged particle would collide with the stationary one after having gone through the magnetic field. Note that the magnetic field does no work on the charged particle, gives it no additional kinetic energy, only changes its direction. If there were no magnetic field, the particles wouldn't collide, but the magnetic field makes them collide and "makes" the second particle move. So it would seem that the magnetic field did work on the other particle, but it didn't, it simply redirected the first particle to hit something it otherwise wouldn't. The energy to do the work came from the kinetic energy of the first particle, yet without the magnetic field the work couldn't not have been done on the other particle. Nevertheless, the magnetic field did no work, it simply redirected a particle's path. In the case of the electric motor, the magnetic field would also simply change the paths of electrons, but would not give them any additional energy. The kinetic energy for the moving wire would come from the kinetic energy the electrons had before. |
| Jul21-12, 10:29 AM | #45 |
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Um, if you say that magnets do no work... Check this out 1 - Yes they can, 2 - Why? 3 - Convinced? If you still need some more "worded" detail check theses links out: 1, 2, As I said before and I will say this again. Magnets/magnetic fields/etc... Are not understood fairly well... I mean so many attention went for complex idea how the most simplest products of nature and most important forces have been underrated....
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| Jul21-12, 11:26 AM | #46 |
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The rebuttal directly before this one by Miyz addresses what we've been talking about. When 2 current loops interact resulting in a net torque, we are examining the work done, forces involved, etc. Please review the link I gave earlier. Rather than repeat what has already been discussed, I will elaborate if you still have questions. Best regards. Claude |
| Jul21-12, 12:57 PM | #47 |
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| Jul21-12, 02:31 PM | #48 |
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It should be similar to the collision. The direction of the electrons is changed and thus allowing them to do work on the wire by colliding with it. Otherwise the collisions would be chaotic, but the magnetic force changes the directions of the electrons in a consistent manner and allows the work to be done at the expense of the electrons kinetic energy, as in the case of a simple collision. |
| Jul21-12, 03:09 PM | #49 |
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The magnets keep their shape by rigid body forces. They may be held stationary on the horizontal plane also by rigid body forces. For instance, the mangets may be attached by glue to the horizontal surface. However, suppose the magnets are not attached directly to the plane. If the magnets are not attached directly to the surface, then there has to be other forces involved. The magnets may have to be held still by a mixture of both gravity, contact force and static friction. The gravity prevents the magnet from moving up. The contact force (i.e., the normal force) prevents the magnet from sinking down. The static friction prevents it from moving in the horizontal plane. Similarly, the wire loop has some weight. If the wire loop is not uniform in thickness, the unbalanced wire could be affected by gravity. The weight of a single carrier may be negligible. However, the weight of other components in the system may not be negligible. The discussion has turned to the contribution of nonmagnetic forces to the work done on the wire loop. The conjecture has been raised that maybe nonmagnetic forces "do work" in a motor. Gravity may well "do work" on a motor. Fortunately, the problem can be solved without enumerating all the forces "that do work". The work done by most of those forces cancel out. By choosing the boundaries on the system properly, one can "hide" the forces that cancel out. In general, this is what has to be done. |
| Jul21-12, 07:41 PM | #50 |
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Claude |
| Jul21-12, 07:41 PM | #51 |
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Claude |
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