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Velocity of a falling object |
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| Aug7-12, 05:39 PM | #1 |
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Velocity of a falling object
1. The problem statement, all variables and given/known data
A ball of mass 0.163 kg is dropped from a height 1.89 m above the ground. The acceleration of gravity is 9.8 m/s^2 Neglecting air resistance, determine the speed of the ball when it is at a height 0.997 m above the ground. Answer in units of m/s 2. Relevant equations Gravitational Energy = Kinetic Energy Mass x Acceleration From Gravity x Height = 1/2 (mass)x(velocity)^2 Acceleration From Gravity x Height = 1/2 (velocity)^2 [mass cancels] 3. The attempt at a solution (9.8 m/s^2) x (1.89m) = 1/2 (velocity)^2 Velocity^2 = 2[(9.8 m/s^2) x (1.89m)] Velocity = ~6.08 m/s 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution |
| Aug7-12, 06:13 PM | #2 |
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| Aug7-12, 06:20 PM | #3 |
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Vf = sqrt 2a delta y?
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| Aug7-12, 06:34 PM | #4 |
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Velocity of a falling object |
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