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Angle of fuzzy dice when moving...Just want to check... |
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| Aug11-12, 01:37 PM | #1 |
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Angle of fuzzy dice when moving...Just want to check...
1. The problem statement, all variables and given/known data
a pair of fuzzy dice hang from your mirror. While you accelerate from a stop on a horizontal surface to 28 m/s in 6 s, what angle θ does the string make with the vertical? 2. Relevant equations tan θ = Y/X a = ΔV / Δt 3. The attempt at a solution Just want a double check: So we can use the accelerations to figure out the angle.... Ay = 9.8 m/s^2 Ax = (Δ V)/ Δ (t) = (28 m/s - 0)/(6 - 0) = 4.7 m/s^2 tan θ = 4.7 / 9.8 = 25.6° |
| Aug11-12, 04:18 PM | #2 |
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Recognitions:
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1. Don't be too free with the "=" symbol; the angle is not the same as the tan of the angle. 2. Keep a few extra decimal places in intermediate results and only round at the end for the final value. |
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