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For each real number x, let f(x) be the minimum of the numbers 4x+1, |
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| Aug31-12, 12:13 AM | #1 |
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For each real number x, let f(x) be the minimum of the numbers 4x+1,
For each real number x, let f(x) be the minimum of the numbers 4x+1, x+2, and -2x+4. What is the maximum value of f(x)?
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| Aug31-12, 12:26 AM | #2 |
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Mentor
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| Aug31-12, 12:36 AM | #3 |
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It is too taken from The Advanced Mathematical Thinking where the author said it can be solved by reversal tactic. Sorry if it is incomplete since I copied whatever written in the book. |
| Aug31-12, 12:52 PM | #4 |
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Recognitions:
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For each real number x, let f(x) be the minimum of the numbers 4x+1,
Is there a range for these numbers, i.e., is x any real number, integer, subset of these
or other? |
| Aug31-12, 06:42 PM | #5 |
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| Sep1-12, 01:05 AM | #6 |
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Recognitions:
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Well, the reason I was asking is that , if the minimum of these numbers is done
over different subsets of the line, then the results will be different. The solution is straightforward: compare the functions and see which of the three dominates over which part of the domain, and construct a piecewise function: set f1>f2 ,f1>f3 , f2>f3 , etc., and select, for each interval the smallest. |
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