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Emission of em wave |
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| Sep1-12, 04:40 AM | #1 |
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Emission of em wave
In wikipedia's description of transmitter, if an alternating current is given to an antenna, then the antenna radiates off em wave.
But why this happens so? |
| Sep1-12, 05:16 AM | #2 |
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Nobody knows - "why" questions are not what science does.
However - the EM waves comes of an accelerating electron because electricity and magnetism are part of the same force. The force is described by Maxwell's equations. The exact description depends on which model you want to use - so some sort of context would hep here. |
| Sep1-12, 08:34 AM | #3 |
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Mentor
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The simplistic description is this:
1. An electric current produces a magnetic field. 2. An oscillating (alternating) electric current produces an oscillating magnetic field. 3. An oscillating magnetic field "produces" an oscillating electric field, which in turn "produces" more oscillating magnetic fields, which in turn "produce" more oscillating electric fields, etc. via the time-derivative terms in Maxwell's equations. These oscillations propagate at speed c. A more accurate version of step 3 is that oscillating magnetic fields are inevitably associated with oscillating electric fields, both propagating at speed c, again via the time-derivative terms in Maxwell's equations. This avoids the implication of a circular cause and effect chain. |
| Sep1-12, 12:57 PM | #4 |
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Emission of em waveThen I think it is also possible to observe visible light from an antenna by controlling frequency of oscillations of its current. Just a thought. |
| Sep1-12, 06:23 PM | #5 |
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| Sep2-12, 02:56 AM | #6 |
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Yah. In principle one could oscillate charges to get optical EM fields ... particularly in the classical model considered here. However, the material properties of the antenna are also important.
We usually exploit some other properties instead ... like heating the metal until it glows. There is a point where the classical "light wave" model stops being useful. |
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