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Relationship between changing a wire's diameter and change in temp |
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| Sep20-12, 03:20 AM | #1 |
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Relationship between changing a wire's diameter and change in temp
1. The problem statement, all variables and given/known data
Hello! I have a problem where I need to develop and justify a hypothesis surrounding the relationship between the thickness (or diameter) of a nichrome wire and the temperature of water that it's submersed in over a time of 5 minutes. (proportionality statement and equations) 2. Relevant equations So far, I know that resistance is inversely proportional to cross-sectional area, and therefore: R ∝ 1/A R ∝ 1/∏r^2 R ∝ 1/∏(d/2)^2 and because 2 and ∏ are constant R ∝ 1/d^2 (resistance is inversely proportional to diameter squared) (I think!) Now, I've also researched Joule's law, which eventuates into: Heat produced = Pt = VIt = V^2/Rt = I^2Rt 3. The attempt at a solution Now, I'm trying to get a relationship between diameter and ΔT, and I thought, so I have R ∝ 1/d^2, and P = V^2/R where V is a constant so P ∝ 1/R and since P is the change in heat: ΔT ∝ 1/R OR since thickness makes resistance go down and less resistance makes ΔT (somehow) then is R ∝ ΔT and substituting so therefore: ΔT ∝ 1/d and I don't have much idea how to reason out what the graph will look like/why... I think I've tied myself in knots... any help would be much appreciated! Thank you!:) |
| Sep20-12, 06:03 AM | #2 |
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I think you have to assume the wire is connected to a constant voltage source and I'd also ignore any change in resistance of the wire with temperature.
Therefore your approach is correct.. R ∝ 1/∏(d/2)2 R ∝ 1/d2 Then use.. Power = V2/R Power = V2 * d2.........................................(1) If the water is in an insulated container then the energy it contains (E) is given by E = Specific heat capacity * mass * Δ Temperature Rearrange to give.. Δ Temperature = E / Specific heat capacity * mass Then.. E = Power * Time so Δ Temperature = Power * Time / Specific heat capacity * mass ...............(2) Put (1) into (2)... Δ Temperature = V2 * d2 * Time / Specific heat capacity * mass Voltage, Time, Specific heat capacity and mass are all constant so Δ Temperature ∝ d2 eg The change in temperature over 5min (not the actual temperature) is proportional to d2 Temperature = Initial Temperature + Δ Temperature So actual temperature is proportional (but not directly proportional) to d2. http://en.wikipedia.org/wiki/Proport...y_(mathematics) |
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| cross sectional area, joule heating, nichrome wire, ohm's law, thermo dynamics |
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