what is the meaning of that a function F is welldefiened ?by Maths Lover Tags: function, meaning, welldefiened 

#1
Nov712, 03:30 PM

P: 62

what does well defiened mean ?
how can we check that a function is well defiened ? 



#2
Nov712, 03:38 PM

Sci Advisor
HW Helper
PF Gold
P: 12,016

That a single input value yields a single output value.




#3
Nov712, 03:40 PM

Mentor
P: 16,652

Let me give an example. Let [itex]\mathbb{Q}[/itex] be the rational numbers. Let's define the following "function":
[tex]f\left(\frac{m}{n}\right)=\frac{m+1}{n+1}[/tex] At the first sight, there is not really a problem. But let's look deeper. We have [tex]f\left(\frac{1}{2}\right)=\frac{2}{3}[/tex] and [tex]f\left(\frac{2}{4}\right)=\frac{3}{5}[/tex] But, as we know, the numbers 1/2 and 2/4 are equal, but the numbers 2/3 and 3/5 are not equal. So the function f sends 1/2 to two different values: 2/3 and 3/5. However, a function is defined as sending a value in the domain to a UNIQUE value in the codomain. Here, we have sent 1/2 to two different numbers, which means that f is not a function. We usually say that ''f is not welldefined'' (I don't think the expression is really formally correct, but it is used everywhere). Another way a function could not be welldefined is that it send something to a value not in the codomain. For example: [itex]f(x)=\sqrt{x}[/itex] is not welldefined if the domain and codomain are both [itex]\mathbb{R}[/itex]. Indeed, [itex]\sqrt{1}[/itex] is not in the codomain. So, if you are given a ''function'', you should always check if a value is being sent to a single other value, and not to multiple values. Furthermore, the value should be in the codomain. Knowing when this is a problem requires a bit of experience, but the problem arises usually in things like ''quotients''. 


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