Register to reply 
Partial differential problem in introductory tensor analysis 
Share this thread: 
#1
Nov812, 03:33 AM

P: 57

So far I have only seen ∂/(∂y) as being interpreted as an operator being of no use unless it is applied to some vector etc.
Now, however, my course literature asserts the following equality: y=∂/(∂y) What is the interpretation of the differentials in this case? 


#2
Nov912, 06:19 AM

P: 323

I suppose is a short way to express [itex]\frac{\partial \psi}{\partial y}=y\psi[/itex].



#3
Nov1512, 04:35 PM

P: 57

Yes, that is a correct statement, but it relies on the asserted equality, so unfortunately it brings nothing new to the party. Luckily I have it all figured out by now, so I thank you for your answer and continue my studies. :)



Register to reply 
Related Discussions  
Partial differential problem  Calculus & Beyond Homework  4  
Partial Differential problem  Calculus  0  
Another partial differential equation problem  Calculus & Beyond Homework  2  
Partial differential equation problem...  Differential Equations  6  
Symmetry Analysis of Partial Differential Equations  Differential Equations  5 