| New Reply |
Partial differential problem in introductory tensor analysis |
Share Thread | Thread Tools |
| Nov8-12, 03:33 AM | #1 |
|
|
Partial differential problem in introductory tensor analysis
So far I have only seen ∂/(∂y) as being interpreted as an operator being of no use unless it is applied to some vector etc.
Now, however, my course literature asserts the following equality: y=∂/(∂y) What is the interpretation of the differentials in this case? |
| Nov9-12, 06:19 AM | #2 |
|
|
I suppose is a short way to express [itex]\frac{\partial \psi}{\partial y}=y\psi[/itex].
|
| Nov15-12, 04:35 PM | #3 |
|
|
Yes, that is a correct statement, but it relies on the asserted equality, so unfortunately it brings nothing new to the party. Luckily I have it all figured out by now, so I thank you for your answer and continue my studies. :)
|
| New Reply |
| Thread Tools | |
Similar Threads for: Partial differential problem in introductory tensor analysis
|
||||
| Thread | Forum | Replies | ||
| Partial differential problem | Calculus & Beyond Homework | 4 | ||
| Partial Differential problem | Calculus | 0 | ||
| another partial differential equation problem | Calculus & Beyond Homework | 2 | ||
| Partial differential equation problem... | Differential Equations | 6 | ||
| Symmetry Analysis of Partial Differential Equations | Differential Equations | 5 | ||