Register to reply

Statics - Method of Sections

by Arty7
Tags: method, sections, statics
Share this thread:
Arty7
#1
Nov10-12, 02:09 AM
P: 7
IHi guys with part b of this question im having trouble. I have cut it it at the specified members and used the top half. Now i take the moment at A to get the force in BC. (CW+)M@A=(6*3)+(6cos(30)*3)=0, But when you solve this it dosnt give you the answer its supposed to be, Im probably blind & missing something. Please check out the attachments i provided some more info on it.

Thankyou in Advance.
Attached Thumbnails
Untitled.png  
Phys.Org News Partner Engineering news on Phys.org
New filter technology uses inert gas to bore holes in high-quality steel
Augmented reality helps in industrial troubleshooting
How wireless technology can dramatically improve ship safety
SteamKing
#2
Nov10-12, 04:40 AM
Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 6,525
No attachments provided.
Arty7
#3
Nov10-12, 04:53 AM
P: 7
Sorry man, its up now

SteamKing
#4
Nov10-12, 11:45 AM
Emeritus
Sci Advisor
HW Helper
Thanks
PF Gold
P: 6,525
Statics - Method of Sections

Where do you get 30 degrees from? Check your triangles.


Register to reply

Related Discussions
Statics Truss Problem Involving Method of Sections Engineering, Comp Sci, & Technology Homework 1
Method of Sections Engineering, Comp Sci, & Technology Homework 1
Statics Question - Method of Sections Engineering, Comp Sci, & Technology Homework 4
Method of sections Engineering, Comp Sci, & Technology Homework 2
Method of Sections Engineering Systems & Design 2