Register to reply 
Utter confusion regarding distance covered during acceleration in free fall. 
Share this thread: 
#1
Nov1612, 11:14 AM

P: 133

Let there be an obj. which is made to fall from a certain height in a gravitaitonal field.
where a= 10 metre per second squared Say it falls for 1 second. v(final velocity)= 10 metre per second. How much distance does it cover in that 1 second? distance = speed x time = avg. speed x 1second = 10 m This means that 10 m is covered during that 1 second. But how could that be when the velocity had not reached 10 metre per second? 


#2
Nov1612, 11:42 AM

HW Helper
P: 7,033

If acceleration is constant, and if the starting speed is 0 meters per second and the final speed is 10 meters per second, then what is the average speed?



#3
Nov1712, 09:54 AM

P: 133

thank you. i understood my mistake.
But now i have another doubt. A body falls freely for 10 metres from rest. what is the final velocity? i found it is sqrt200. am i right? i found sqrt200. am i right? 


#4
Nov1712, 02:13 PM

HW Helper
P: 7,033

Utter confusion regarding distance covered during acceleration in free fall.



Register to reply 
Related Discussions  
Distance covered in free fall  Classical Physics  2  
Distance covered under variable acceleration  Classical Physics  2  
Free fall: total distance expressed in terms of distance fallen in nth second  Introductory Physics Homework  6  
Utter Confusion on Projectile Motion  Introductory Physics Homework  3  
Totally Lost (Free Fall Distance)  Introductory Physics Homework  2 