# Utter confusion regarding distance covered during acceleration in free fall.

by AakashPandita
Tags: acceleration, confusion, covered, distance, fall, free, utter
 P: 128 Let there be an obj. which is made to fall from a certain height in a gravitaitonal field. where a= 10 metre per second squared Say it falls for 1 second. v(final velocity)= 10 metre per second. How much distance does it cover in that 1 second? distance = speed x time = avg. speed x 1second = 10 m This means that 10 m is covered during that 1 second. But how could that be when the velocity had not reached 10 metre per second?
 HW Helper P: 6,788 If acceleration is constant, and if the starting speed is 0 meters per second and the final speed is 10 meters per second, then what is the average speed?
 P: 128 thank you. i understood my mistake. But now i have another doubt. A body falls freely for 10 metres from rest. what is the final velocity? i found it is sqrt200. am i right? i found sqrt200. am i right?
HW Helper
P: 6,788

## Utter confusion regarding distance covered during acceleration in free fall.

 Quote by AakashPandita A body falls freely for 10 metres from rest. what is the final velocity? i found it is sqrt200.
Correct. You can also write this as 10 x sqrt(2) or ~14.1421. I'm not sure what form of answer your class would prefer.

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