Register to reply 
Conservatino of Momentum 
Share this thread: 
#1
Nov1812, 04:32 AM

P: 3

I know the totoal momentum and the total energy is conserved during the collision.
And total energy is equal to the internal energy and the kinetic energy of the object. But I still can not see the internal energy from the formulea which only involve m and v. For me, it seems that if mv is conserved so should 1/2mv^2 be. It is just a little bit confusing that where does this 'internal energy' come from 


#2
Nov1812, 08:08 AM

P: 949

"Internal energy" in the sense meant here is the energy that a system has even when that system as a whole is not moving. This can include a lot of things.
In the usual case, two objects that collide and lose kinetic energy will gain thermal energy. They will be a little bit warmer after the collision. If you bend a metal rod repeatedly you can easily feel an example of this kind of heating. Depending on the scenario, the lost (or gained!!) energy in a collision can take the form of heat energy, chemical energy, electrical energy, light, sound, tension in springs, gravitational potential energy and many other things. 


#3
Nov1812, 10:23 AM

P: 3




#4
Nov1812, 01:48 PM

P: 1,020

Conservatino of Momentum
momentum is a vector and energy is a scalar quantity.



#5
Nov1812, 02:42 PM

P: 615

Using the definition of momentum, we say that [itex]\vec{p}[/itex] = m[itex]\vec{v}[/itex]. Here, [itex]\vec{v}[/itex] is the velocity of the object, which is a vector. Thus, momentum is a vector and energy is a scalar. Also, energy and momentum are different because they mean different things. For example, if we wanted to put them in terms of standard SI units, we could say that momentum is measured in Newton seconds and energy is measured in Newton meters. 


#6
Nov2212, 05:38 PM

P: 34

My book ( Chapter 10 ) says both are conserved:
MV = m1v1 + m2v2 ( in explosion problems ) and Ktotal = 1/2 m1v1^2 + 1/2m2v2^2 but note ( for some reason ?? ) Ecm = 1/2 (m1 + m2) Vcm^2 is not equal to Ktotal I think your answer is somewhere in this mess ( book is Ohanian ). And I'm getting the book answers using these equations. 


#7
Nov2212, 09:39 PM

P: 741

A chemical bond, a cohesive bond, or some other bond is broken. In that case, the macroscopic kinetic energy is not conserved. The energy goes into random motions of the atoms. If you fire two cannon balls at each other, and the cannon balls stick together, bonds are formed. The two cannon balls may lose all their macroscopic kinetic energy. However, their temperature goes up. Thus, there is a lot of internal energy (sometime called heat energy) generated. The cannon balls may stop and fall. However, their total momentum hasn't changed. The combined momentum of the cannon balls was zero before and after the collision. The tricky part is knowing when heat energy is generated. In other words, one has to recognize when entropy is generated. I always look for something that breaks. If anything breaks, then I know thermal energy is generated. If nothing breaks, then thermal energy is not generated. 


#8
Nov2212, 11:22 PM

Sci Advisor
P: 2,470




Register to reply 
Related Discussions  
Angular momentum: why can't I answer this problem using linear momentum rules?  Introductory Physics Homework  2  
Poincare conserved currents : Energymomentum and Angularmomentum tensors  Beyond the Standard Model  10  
Aircraft Carrier  Linear Momentum converted to Angular Momentum and Impact Force  Engineering, Comp Sci, & Technology Homework  0  
Momentum operator for a free particle with a definite momentum and Energy  Quantum Physics  3  
Conservatino of Momentum: Bowling Ball and Earth  Introductory Physics Homework  1 