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I can't find the limit absolute value function. 
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#1
Nov2212, 02:27 PM

P: 14

Hi everybody,
I can't find the limit of (abs(x2)2)/x as x>1. I know it's (1) but I don't see how you get to it. If I take (x2)>0 I get L=3,(x2)<0 I get L=1. However according to the graph two sided limit does exist and it's (1). Please help Thanks 


#2
Nov2212, 03:14 PM

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RGV 


#3
Nov2212, 03:48 PM

P: 14

is it just a "plugin" problem?
(122)/1 => (12)/1 => (12)/1 =1? 


#4
Nov2212, 04:53 PM

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I can't find the limit absolute value function.
RGV 


#5
Nov2212, 07:35 PM

P: 14

The value of function is negative(?)



#6
Nov2212, 09:36 PM

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RGV 


#7
Nov2212, 11:51 PM

P: 14

f(x)=1



#8
Nov2312, 07:43 AM

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P: 39,348

Good! For all x less than 2, f(x)= 1 so the limit at any x less than two is 1.



#9
Nov2312, 01:15 PM

P: 14

thank you HallsofIvy and Ray



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