# I can't find the limit absolute value function.

by Vola
Tags: absolute value, calculus, limit
 P: 14 Hi everybody, I can't find the limit of (abs(x-2)-2)/x as x-->1. I know it's (-1) but I don't see how you get to it. If I take (x-2)>0 I get L=-3,(x-2)<0 I get L=-1. However according to the graph two sided limit does exist and it's (-1). Please help Thanks
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P: 5,014
 Quote by Vola Hi everybody, I can't find the limit of (abs(x-2)-2)/x as x-->1. I know it's (-1) but I don't see how you get to it. If I take (x-2)>0 I get L=-3,(x-2)<0 I get L=-1. However according to the graph two sided limit does exist and it's (-1). Please help
What happens when x is near 1?

RGV
 P: 14 is it just a "plug-in" problem? (|1-2|-2)/1 => (|-1|-2)/1 => (1-2)/1 =-1?
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P: 5,014
I can't find the limit absolute value function.

 Quote by Vola is it just a "plug-in" problem? (|1-2|-2)/1 => (|-1|-2)/1 => (1-2)/1 =-1?
What is your answer to the question I asked you?

RGV
 P: 14 The value of function is negative(?)
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P: 5,014
 Quote by Vola The value of function is negative(?)
Let me ask it one last time: if f(x) = (|x-2|-2)/x, what would be the simplified formula for f(x) when x is near 1? Don't guess---calculate!

RGV
 P: 14 f(x)=-1
Math
Emeritus