
#1
Nov2312, 03:54 AM

P: 18

1. The problem statement, all variables and given/known data
It is said that good ice skating only occurs when the ice below the skates melts. Using the ClausiusClapeyron equation, estimate the coldest temperature at which good ice skating can occur. (Water expands 9% on freezing, Latent heat of ice melting is 334 kJ/Kg, the contact area is 1mm by 5cm and the skater weighs 70kg, water has a molar mass of 18g) 2. Relevant equations [itex]\frac{dp}{dT}[/itex] = [itex]\frac{L}{T(V_{2}V_{1})}[/itex] or I think rearranged like this [itex]p_{0}[/itex]p = [itex]\frac{L}{\DeltaV}[/itex] ln[itex]\frac{T_{0}}{T}[/itex] 3. The attempt at a solution I have found the pressure exerted as 1.372 x [itex]10^{7}[/itex] kg/[itex]m^{2}[/itex] I realise that we want the ice to be melting.. so 273k at this pressure, so I need to find the temperature at normal room pressure of 101 KPa. However I dont know what to use for the volume? 



#2
Nov2312, 10:11 AM

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P: 4,481

[itex]\frac{\Delta p}{\Delta T}[/itex] ≈ [itex]\frac{L}{T(V_{2}V_{1})}[/itex] 



#3
Nov2512, 01:08 PM

P: 2

... and the answer comes out around 1.0 degree ??




#4
Nov2512, 02:00 PM

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Thanks ∞
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P: 4,481

Thermal Physics: Ice skating temperatures
Yes..which debunks the idea that ice skates slide well on ice due to pressure causing the ice to melt and become slippery.
See http://www.nytimes.com/2006/02/21/sc...pagewanted=all 



#5
Nov2512, 02:03 PM

P: 2

Agreed ... it is far more complex.



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