Register to reply 
Rotational Motion Quantities 
Share this thread: 
#1
Dec1012, 08:26 AM

P: 937

Hello,
Of the different rotational quantities of motionangular velocity, angular acceleration, torque, angular momentum, etc., which of them has their direction perpendicular to the plane of rotation (not sure if I worded that correctly)? I am pretty certain that torque has its direction perpendicular to the plane of rotation. I've tried to research why that is, but most people say that it is simply mathematical convention, and that there is no physical reason why, or something to that effect. But I feel like if angular velocity, a quantity that is well defined, has its direction perpendicular to the plane of rotation, then we can use this fundamental quantity to reason about the others, which may give us more insight as to why they have their direction perpendicular to the plane of rotation. I'm sorry if this isn't exactly coherent; this is just a stream of thoughts, and is the only way I can seem to articulate it. 


#2
Dec1012, 09:06 AM

Mentor
P: 11,626

Rotational kinetic energy is not a vector (similarly to translational kinetic energy). 


#3
Dec1012, 10:05 AM

P: 937




#4
Dec1012, 10:34 AM

Mentor
P: 11,626

Rotational Motion Quantities
The vectors have their direction along the axis of rotation, and their magnitudes calculated according to the usual formulas: ##\omega = v/r## for angular velocity, ##\alpha = a/r## for angular acceleration, ##\tau = rF \sin \theta## for torque, etc.
Or have I misunderstood your question? 


#5
Dec1012, 11:10 AM

P: 937

Well, I know how their magnitudes are quantified, but you said that you use vectors to describe the direction of the different rotational quantities, what vectors are you using?



#6
Dec1012, 11:43 AM

P: 293




#7
Dec1012, 12:31 PM

P: 886

There is no physical reason why torque or any other rotational quantity follows the right hand rule. This is purely a convention. Note that we are allowed to have angular momentum in 2D space, where angular momentum is described by a scalar, not a vector.
The truth is that these angular quantities do not live in the same "space" as our regular vector quantities, but in a 2form, where the basis vectors are formed with pairs of the original directions. For example: the basic directions in regular 3D space are x, y, and z. The basic directions for the space for angular momentum are x^y, x^z, and y^z. Rotation in the xy plane is given by a vector in the x^y direction. (We still need to use a sign convention (the right hand rule), but we can regard x^y as y^x.) (^ should be read as the wedge product, not an exponent). Notice that if the "regular" space is 3D, the angular momentum space is also 3D. This makes it handy to "relabel" the basis vectors using regular vectors. Refer to x^y as the z direction, y^z as x, z^x (or x^z) as y. We say that the regular 3D space is "dual" to the angular 3D space. But if the "regular" space is 2D, the angular momentum space is 1D (the only direction is the x^y direction). In 4D (useful for relativity), there are 6 angular momentum directions. 


#8
Dec1012, 02:54 PM

Mentor
P: 11,626

Suppose our record is rotating in a horizontal plane, counterclockwise as viewed from above. Then the direction of the angular velocity is upwards, in the +z direction. In this case, ##\hat n = \hat z##, the unit vector in the +z direction, and $$\vec \omega = (3.49 \text{ rad/s}) \hat n = (3.49 \text{ rad/s}) \hat z$$ Suppose we now tilt the turntable that the record is rotating on, downwards by 30° in the +x direction. The unit vector now points 30° away from the +z direction, towards the +x direction. Using a little trigonometry we find $$\hat n = \left( \frac{1}{2} \hat x + \frac{\sqrt{3}}{2} \hat z \right)$$ and the new angular velocity is $$\vec \omega = (3.49 \text{ rad/s}) \hat n = (3.49 \text{ rad/s}) \left( \frac{1}{2} \hat x + \frac{\sqrt{3}}{2} \hat z \right) = (1.75 \text{ rad/s}) \hat x + (3.02 \text{ rad/s}) \hat z$$ 


#9
Dec1112, 05:25 AM

Mentor
P: 15,067

Suppose you apply a nonzero torque to the rotating body. There's nothing forbidding you from applying a torque about some axis other than the axis of rotation. You can apply a torque about any axis, not just the axis of rotation. The body isn't going to suddenly jump to this new axis of rotation just because you applied a torque about that new axis. In general, the only thing amongst angular velocity, angular momentum, and torque that is perpendicular to the plane of rotation is angular velocity. As discussed above, torque can be pointing anywhere. Angular momentum is parallel to angular velocity only in the special case where the body is rotating about a principal axis. Otherwise, it's pointing somewhere else (and then you get some rather funky classical physics). Rotation in 3 dimensional space is quite unique. 3D space is the only space where angular velocity looks like a vector in that space. (Better: It's a pseudovector.) In 2D space, angular velocity, angular momentum, and torque are just scalars. (Better: they're pseudoscalars.) In 4D space, angular velocity has six degrees of freedom. As Khashishi mentioned, angular velocity is a 2form (a skew symmetric matrix). In general, the number of degrees of freedom in an NxN skew symmetric matrix is N*(N1)/2. To look like a vector in Nspace, we must have N*(N1)/2=N. The only nontrivial solution is N=3. This is what makes 3D rotation so unique. Orientation and rotation are difficult concepts, much harder to grasp than position and translation. High school and freshman physics classes keep rotation simple by only presenting problems where rotation is restricted to a single axis (single plane). The sophomore/junior level classical physics class starts to investigate rotation in 3D space, but even then it doesn't quite get into the whys and hows. There's quite a bit of handwaving with regard to orientation and rotation in all but the honors versions of those sophomore/junior level classical physics classes. Group theory is needed to get a better understanding of orientation and rotation. Physics students typically aren't (or weren't) introduced to group theory in their undergrad classes. That's done in introductory graduate level physics classes, and even group theory doesn't quite cut it. To truly understand orientation and rotation you need to know a bit about Lie groups and Lie algebras. 


Register to reply 
Related Discussions  
Equations of motion of a particle over a cone+conserved quantities  Advanced Physics Homework  9  
Equations of motion of a particle over a cylinder+conserved quantities  Advanced Physics Homework  5  
Projectile Motion (Vector Quantities)  Introductory Physics Homework  2  
Projectile Motion (Vector Quantities)  Introductory Physics Homework  5  
Equation of trajetory+conserved quantities of a motion over a sphere  Advanced Physics Homework  6 