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Statistical mechanics - Partition function of a system of N particles |
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| Jan2-13, 10:35 PM | #1 |
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Statistical mechanics - Partition function of a system of N particles
1. The problem statement, all variables and given/known data
Imagine a system with N distinguishable particles. Each particle may be in two states of energy: -ε and +ε. Find the the partition function of the system 2. Relevant equations ![]() 3. The attempt at a solution I know that I have to find the partition function for a single function, Z, and my final result will be ZN. Now, I'll say that: (Where it says ε it's meant to be ε(r) ) Z = Ʃr exp(-β(ε - ε) ) = Ʃr exp(-βε) * exp(βε) = = Ʃr exp(-βε) * Ʃr exp(βε) I'm sure this is incorrect. It doesn't make sense in my head.. E(r) is the energy associated with each microstate, therefore saying that E(r) = ε(r) - ε(r) can't make any sense! I know that the result is: Z = ( exp(βε) + exp(-βε) )N I have no idea how to get there tho. How did it became a sum? How do I get rid of the summatories? Any help will be appreciated! Thanks. |
| Jan2-13, 11:01 PM | #2 |
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The partition function is a summation over states. You simply are using the summation wrong. It is not a summation over the energy levels of within the exponent. It is a summation over e(-Es/T).
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| Jan2-13, 11:03 PM | #3 |
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Look at any example problem in a thermo book for a 2-state system
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| Jan3-13, 09:39 AM | #4 |
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Statistical mechanics - Partition function of a system of N particles
8ikmAm I not summing over the expoent of the energy of each microstate?
EDIT: Is it a summation over all the states of energy instead of the energies of each microstate? Because then the solution would make sense! |
| Jan3-13, 09:55 AM | #5 |
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A good book is Thermal Physics by Kittel + Kroemer |
| Jan3-13, 10:00 AM | #6 |
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Where Es is the energy of the s-th state
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