Equilibrium - The physics of a clothesline.

by L_0611
Tags: clothesline, equilibrium, physics
L_0611 is offline
Jan3-13, 01:47 AM
P: 24
1. The problem statement, all variables and given/known data

A clothesline is attached to two fixed ends which are 10.0m apart. A pulley of mass 40.0kg hangs freely in the middle of the line. The sag at the centre is 0.20m. Find the tension in each half of the clothesline.

2. Relevant equations

3. The attempt at a solution

not sure how to tackle this problem since I don't have the values for the angle θ that is formed at the centre. Please point me towards the right direction with this problem. Thank you.
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ehild is offline
Jan3-13, 01:51 AM
HW Helper
P: 9,834
Make a drawing and you will find the angle.

L_0611 is offline
Jan3-13, 01:30 PM
P: 24
ok so I made a drawing like ehild recommended and I think I figured out angle θ. This is what I got for an answer.

tanθ = 5/0.2 = 25
θ = tan-1*25 = 87.7

then then formula I used to solve the problem would be 2Tcos87.7=mg

then i rearranged the formula to read:
T= 4884N

Therefore the tension on each half of the clothesline is 4884N.

please correct me if I'm wrong on this problem. Thank you.

grzz is offline
Jan3-13, 01:48 PM
P: 939

Equilibrium - The physics of a clothesline.

Your solution is ok.
L_0611 is offline
Jan3-13, 01:55 PM
P: 24
ok perfect, thank you. As part of my solution I'm asked to find the x and y components but I'm not sure how to do so, can anyone help me? they want me to use these five steps to solve the problem, the steps are as follows:
Step 1: select the object to be studied.
Step 2: draw a "free-body diagram" for each object chosen.
Step 3: choose a set of x and y axes for each of the objects being analyzed, and resolve the free-body diagram into components that point along these axes. (this is the step I'm having issues with).
Step 4: set up the equations in such a way that the sum of the x-components of the forces is zero, and the sum of the y-components is also equal to zero.
Step 5: solve the equations for the unknown quantities you are looking for.

Again, thanks for your help.
MrWarlock616 is offline
Jan3-13, 02:00 PM
P: 154
How did you get the equation 2Tcos87.7=mg before? Describe this in steps for them.
L_0611 is offline
Jan3-13, 02:01 PM
P: 24
ok so that's basically all I have to do? put it into words...?
MrWarlock616 is offline
Jan3-13, 02:08 PM
P: 154
Yeah man!!
L_0611 is offline
Jan3-13, 02:08 PM
P: 24
Alright then, funny how sometimes I can miss the simplest things, thanks a lot.

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