Energy transfer in electromagnetic inductionby entropy15 Tags: electromagnetic, energy, induction, transfer 

#37
Dec3112, 01:41 PM

PF Gold
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#38
Dec3112, 02:56 PM

P: 37

The delay for the magnet to experience resistance due to the current in the coil seems to be 2x/c. Indeed, If we follow the classical approach the delay seems to be 2x/c. But if we look at it from QED perspective it seems to be 0. (Wheeler Feynman absorber theory) Can we throw more light on it looking at it from the relativity perspective? After all magnetic field can be explained as an effect due to the "length contraction" involving moving charges using theory of relativity. I have seen papers which explain the origin of magnetic fields using relativity. Most of them have to do with the forces of attraction/repulsion between two wires carrying current. But I have not come across any which explain electromagnetic induction with the same approach. I know it would be too complicated, but in case any of you have come across it, please help. 



#39
Jan413, 10:12 AM

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P: 3,337

Drakkith has got a good point. There are two different situations 1) considering a magnet which is being given a 'nudge' by some person. 2) considering a magnet which is moving toward the coil, with no 'outsider' forces.
I have mostly been talking about what happens when the magnet is given a 'nudge' i.e. acceleration. In this case, there is a delay before the effect is felt by the coil. I am pretty sure that Wheeler Feynman absorber theory also predicts that there is a time delay. But because I don't know much QFT, I can't say with complete certainty. Now in the case when the magnet is moving freely (not being 'nudged'), then I am not so sure about whether there is a delay in the reaction force being felt, because in this case, at any particular time, there is already a magnetic field travelling between the magnet and the coil (which is due to the magnet moving at an earlier time). 



#40
Jan413, 02:30 PM

P: 1,027

However, the magnet will feel small resistance immediately. This is due to the fact that one part of the surface current will act on another, an in case the magnet is accelerated, these forces do not cancel each other but tend to act against the acceleration. This is sort of a "selfinductance" effect. Later, after time 2x/c, the wave from the coil will come and damp the magnet as well. This will be typically much greater effect (sort of "mutual inductance"). 



#41
Jan513, 01:47 PM

P: 37

Suppose that the magnet is initially at rest. It is given a push at time t=t1. Lets assume that the kinetic energy transferred to the magnet due to this push is E_{k}. This kinetic energy may decrease immediately due to radiation or self inductance but the effect is negligible. Now at time t=t1+(x/c) we have the current induced in the coil and it has gained energy due to this induced current. Now since the magnet does not experience any resistance till t1+(2x/c) i.e any considerable resistance we can see that the magnet does not lose the kinetic energy acquired by it during the initial push till t1+(2x/c). So between t1+(x/c) and t1+(2x/c) we have this energy in the coil as well as in the kinetic energy of the magnet. The kinetic energy of the magnet is the cause for the current to be induced in the coil. The magnet just transfers its kinetic energy to the coil through mutual induction. So should not the kinetic energy of the magnet decrease before the current is induced in the coil? 



#42
Jan513, 02:23 PM

P: 1,027

You are probably worried about conservation of energy, but I think there is no problem. The currents in the coil get their energy from the field near the wires. Eventually, the magnet will lose some kinetic energy, but this is merely an aftereffect. 



#43
Jan513, 03:00 PM

P: 37

The energy stored inside the magnetic field is constant. If the current gets energy from the field surrounding the coil, how can it obtain more and more energy from this field as the velocity of the magnet increases. If the magnet is moving with a sufficiently high velocity the current induced in the coil may increase beyond what the surrounding magnetic field can provide. 



#44
Jan513, 03:09 PM

P: 37

So this should get rid of the energy conservation problems. In this case the resistance is felt immediately rather than 2x/c. 



#45
Jan513, 03:33 PM

P: 1,027

The energy of the field is the higher the higher is the velocity of the magnet. We can be sure that there is always enough energy present to maintain the energy conservation, because we have the Poynting theorem; this shows that the energy is conserved locally, and moves through space like fluid.. I agree it is difficult to imagine this in such complicated process, but there is an alternative way of description, via EM forces, which makes this much more clear. According to the Faraday law, the magnitude of the electric field due to magnet animating the currents is the higher the higher is the velocity of the magnet; the higher the electric field, the stronger currents get induced. 



#46
Jan513, 03:55 PM

Mentor
P: 16,479

I see the scenario as follows: 1) magnet and coil at rest wrt each other, no forces 2) force on magent to accelerate magnet (extra force required in order to generate E field) 3) EM wave propagates at c to coil 4) changing current induced in coil 5) changing field produced by coil 6) EM wave propagates at c to magnet 7) coil field opposes motion of magnet I recommend against throwing unnecessary quantum concepts into any discussion which can be done purely classically. Generally it adds more confusion than understanding. 



#47
Jan513, 06:30 PM

HW Helper
P: 3,337

Edit: So I guess I'm saying that if we only considered mutual inductance, then energy is not conserved when we give the magnet a nudge. (But this is because we are not considering the whole picture). 



#49
Jan613, 02:46 AM

P: 37

Thanks for replying to my queries. One more thing here, suppose that we replace the magnet with an electromagnet. The current in the electromagnet is controlled by a switch. Also we will remove the coil.(which was originally placed at a distance x) Initially the electromagnet is not powered on and hence no magnetic field would be present. Now we nudge this electromagnet so that it starts moving at a constant velocity. Next the electromagnet is switched on so that it produces a magnetic field. Now since it is moving, it should try putting energy to the electromagnetic field. So wont this oppose the current flowing in the electromagnet itself? trying to decrease the magnetic field. 



#50
Jan613, 02:48 AM

P: 37





#51
Jan613, 10:17 AM

PF Gold
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#52
Jan613, 11:37 AM

P: 37

But what if we repeat the original experiment of the magnet and coil by replacing the permanent magnet with this electromagnet. Initially the electromagnet is turned off. Then it is nudged so that it moves at a constant velocity v. Now we power on the electromagnet at instant t=t1. When will the current be induced in the coil (which is at a distance x) and when will the electromagnet experience resistance? Would the results be similar to what we get when we had the permanent magnet there or is it different with an electromagnet? 



#53
Jan613, 01:51 PM

Mentor
P: 16,479

What do you think? What would you expect to be similar and what would you expect to be different in this case?




#54
Jan613, 05:36 PM

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P: 3,337

I am impressed by entropy15's perseverance at trying to understand this problem fully :) The point I think he is trying to make is that when the electromagnet gets switched on, there is a delay of 2x/c before it feels the resistance due to mutual inductance (or slightly less, since it is moving at some constant velocity). But the current is induced in the coil after a delay of only x/c. So his (implied) question is "where did the energy go?"
The problem is most simple when the magnet and coil are stationary with respect to each other (and then we can do a Lorentz transform to find the answer for when the magnet is moving at constant velocity WRT the coil). So for now, I will assume the electromagnet is stationary WRT the coil. Now, when the electromagnet is switched on, a wave will be emitted, immediately carrying energy away from the magnet (this doesn't care if the coil is there or not). And if the coil is there, some of the energy will be taken out of the EM field to start moving the charges around the coil. Now if the electromagnet were moving with some constant velocity WRT the coil, then a similar thing will happen when the switch is flicked on. (i.e. the electromagnet emits a wave of energy). And after a short time, the current through the electromagnet will become approximately constant. So after the delay of x/c, the coil will feel a brief EM wave, then a steady magnetic field that is slowly increasing because the magnet is getting closer to the coil. So after some time, the electromagnet will start feeling resistance due to mutual inductance. From this explanation, there is no problem that initially the coil has an induced current, while the magnet feels no resistance from mutual inductance, because initially, when the switch was turned on, the electromagnet released some energy into the EM field. So the situation satisfies energy conservation. Edit: WRT means "with respect to" and EM means "electromagnetic". Also I should say, my whole explanation hinges on the assumption that a stationary electromagnet will emit an electromagnetic wave when it is first switched on. I am pretty sure this is right. 


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