Graphing Covariant Spherical Coordinatesby jstrunk Tags: coordinates, covariant, graphing, spherical 

#1
Jan613, 04:33 PM

P: 8

I am studying Riemannian Geometry and General Relativity and feel like I dont have enough practice with covariant vectors. I can convert vector components and basis vectors between contravariant and covariant but I cant do anything else with them in the covariant form. I thought converting the familar graph of spherical coordinates to its covariant equivalent and plotting some covariant vectors on it would be a good exercise. I spent but a lot of time on it and couldnt do it.
Does anyone know where I can find some good excerises like this or a drawing of the covariant equivalent of spherical coordinates? 



#2
Jan713, 09:16 PM

P: 111

I didn't think there was a difference between the contravariant and covariant spherical basis vectors because they're orthogonal even though they are positionally dependent.
If your mission is to mess around with covariant basis vectors in 3 dimensions (in a visual geometric way), in solid state physics you can mess around with the reciprocal lattice vectors for various lattice types. The reciprocal lattice vectors are the dual basis vectors (covariant basis vectors/contravariant vector components) for the lattice vectors, so you can mess around and see what these reciprocal lattices actually look like. 



#3
Jan913, 07:07 PM

P: 8

I dont really understand your reply. The only coordinate system where the covariant and contravariant bases are the same is Rectangular Coodrinates. I have no idea what reciprocal lattice vectors are or how to find exercises using them.




#4
Jan1113, 08:42 AM

P: 280

Graphing Covariant Spherical Coordinates
It's not spherical coords but maybe this video can help you out if you haven't watched it already (the drawing starts at about 4.00):
http://www.youtube.com/watch?NR=1&v=...ture=endscreen 



#5
Jan1113, 02:03 PM

P: 111

Basically it's just using the equations linking covariant and contravariant basis vectors:[tex]\vec{e}^{1} = \frac{\vec{e}_{2} \times \vec{e}_{3}}{\vec{e}_{1} \circ (\vec{e}_{2} \times \vec{e}_{3})}[/tex] [tex]\vec{e}^{2} = \frac{\vec{e}_{3} \times \vec{e}_{1}}{\vec{e}_{1} \circ (\vec{e}_{2} \times \vec{e}_{3})}[/tex] [tex]\vec{e}^{3} = \frac{\vec{e}_{1} \times \vec{e}_{2}}{\vec{e}_{1} \circ (\vec{e}_{2} \times \vec{e}_{3})}[/tex] to change between a set of nonorthogonal basis vectors that represent a crystal's structure to what the crystals look like in "reciprocal space". It's just this kind of a thing: I dunno, I'm thinking my suggestion is too far from helpful ._. It's too complicated for what looks to be not a lot of enlightenment :/ I remembered it being more enlightening than it's turning out to be.. Though I was trying to appeal from something in physics rather than just straight mathematics. 


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