
#1
Jan2213, 05:09 AM

P: 247

The function f is continuous at some point c of its domain if the limit of f(x) as x approaches c through the domain of f exists and is equal to f(c). In mathematical notation, this is written as
[itex]lim_{x\rightarrow c}[/itex] f(x) = f(c) from the positive and negative sides . For ln(x) (the natural log of x), as x[itex]\rightarrow[/itex]0 , ln(x) approaches [itex]\infty[/itex] Hence I would stand by the notion that ln(x) is not continuous since at x=0, the function is not defined . Also, the graph does not exist in x<0 domain ; so ln(x) can never approach [itex]\infty[/itex] from the ve "x" side . 



#2
Jan2213, 05:22 AM

Sci Advisor
P: 778

A function is continuous if it continuous at every point in its domain. The domain of natural logarithm (when treated as a real function) is ##(0,\infty)##. Zero is not part of the domain of log.




#3
Jan2213, 05:22 AM

P: 418

The part you seem to forget is "some point c of its domain". 0 is not in the domain of ln so this is why your observation is not a problem. The domain of ln is the positive numbers.
It is however an interesting observation in its own right and it implies that you cannot possibly define ln(0) in such a way that the extension would be continuous. 



#4
Jan2213, 06:42 AM

P: 247

Natural Log : seems as a discontinous function
extending the idea you proposed, would it be logical to assume that each and every log(x) function has a domain (0,infinity) ?




#5
Jan2213, 06:48 AM

P: 418

This is a slight lie because in complex analysis we actually extend log and define it for many complex numbers. However we will never be able to include 0 in the domain (without making it discontinuous), and this little side remark is not important to you right now. 


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