# Finding a limit

by Mathoholic!
Tags: limit
 P: 49 I'm familiarized with finding limits of most kinds of functions. I was struck by a problem: What if the variables of the function belong to different sets of numbers? My point being, given the function: f(n,q)=$\frac{n}{q}$ With n belonging to the set of natural numbers and q belonging to the set of rational numbers. How do I avaluate the following limit (if possible): lim f(n,q) as n→∞ and q→∞ This may be a silly question but care to answer please. Thank you
 P: 83 I am not 100% certain but I believe L'Hospital's rule still applies to multivariable functions if both the top and bottom functions are going to infinity. That would make: lim f(n,q) as n→∞ and q→∞ = 1 only because you can take the derivative of what is upstairs and the derivative of what is downstairs with simplicity. I don't think this method would work if you had say, a function like: f(n,q) = (n+q) / (q-n)^2 because then you would have multiple variables locked upstairs and downstairs and it would become a mess with partial derivations.
 PF Gold P: 330 That function is discontinous along one axis. Don't think L'Hospital can be used then.
HW Helper
P: 2,954
Finding a limit

 Quote by Mathoholic! I'm familiarized with finding limits of most kinds of functions. I was struck by a problem: What if the variables of the function belong to different sets of numbers? My point being, given the function: f(n,q)=$\frac{n}{q}$ With n belonging to the set of natural numbers and q belonging to the set of rational numbers. How do I avaluate the following limit (if possible): lim f(n,q) as n→∞ and q→∞ This may be a silly question but care to answer please. Thank you
You have to define your n and q better.

As an example, let's take the limit ##\lim_{x \rightarrow \infty} \frac{\lfloor x \rfloor}{x}##, where ##x \in \mathbb{R}##

You can't simply apply L' Hopital's because the numerator is a discontinuous function.

But you can find the limit by defining the fractional part of x as ##\{x\}## and rewriting the limit as:

##\lim_{x \rightarrow \infty} \frac{x - \{x\}}{x} = 1 - \lim_{x \rightarrow \infty} \frac{\{x\}}{x} = 1##

So a lot depends on exactly what you intend the numerator and denominator to signify.