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On continuous and locally one-to-one map

 
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Jan31-13, 10:00 AM   #1
 

On continuous and locally one-to-one map


Whether a continuous and locally one-to-one map must be a (globally) one-to-one map? If the answer is not. Might you please give a counter-example? Thank in advance.
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Jan31-13, 10:35 AM   #2
 
The answer is no. Consider the mapping [itex]\mathbb{R} \rightarrow S^1[/itex] defined by [itex]x \mapsto \exp(2\pi i x)[/itex].
Jan31-13, 11:03 AM   #3
 
Got it, many thanks!

Another question: whether a continuous and locally one-to-one map between two open spaces, e.g., two connected open set of R^n, must be a (globally) one-to-one map?
Jan31-13, 11:53 AM   #4
 
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On continuous and locally one-to-one map


Quote by krete View Post
Got it, many thanks!

Another question: whether a continuous and locally one-to-one map between two open spaces, e.g., two connected open set of R^n, must be a (globally) one-to-one map?
No, consider

[tex]\mathbb{C}\setminus \{0\}\rightarrow \mathbb{C}:z\rightarrow z^2[/tex]
Jan31-13, 12:11 PM   #5
 
Thanks a lot!
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