## KVL Exercise - Basic

1. The problem statement, all variables and given/known data
https://www.diigo.com/item/image/2sb3i/yjim

2. Relevant equations
KVL Law
Similar Example :
https://www.diigo.com/item/image/2sb3i/orwa

3. The attempt at a solution
(a)
In the left loop :
-8-12+VR2 = 0
VR2 = -20 v

(b)
In the big loop :
-8-12+7-9-V2-3+VR1 = 0
-8-12+7-9-V2-3+1 = 0
V2 = -24

Why is my solution wrong?

If I take the right loop for (b) using the right answer for (a) :
-4+7-9-V2-3+1 = 0
V2 = -8 which is true.

Is the wrong with the negative voltage (-8) ??

thanks.

Recognitions:
Homework Help
 Quote by Ammar w Is the wrong with the negative voltage (-8) ??
Yes, it looks like whoever created the circuit diagram created confusion when they labeled the leftmost resistor's potential drop. As it is marked, strictly speaking there should be a -8V potential drop across that resistor proceeding from bottom to top, which translates into a +8V potential rise as you've properly interpreted it. However, it would appear that they (confusingly) intended the "+ -" indicators to show the actual direction of the potential change of 8V.

Bottom line: assume that the "-8V" is really "8V" oriented according to the "+ -".
 thank you but I see that there is no difference if it was "+8" instead of "-8" ???

Recognitions:
Homework Help

## KVL Exercise - Basic

 Quote by Ammar w thank you but I see that there is no difference if it was "+8" instead of "-8" ???
Um, how can it make no difference if you change the sign of a potential change?

For part (a) your equation summing the potential drops would become: +8-12+VR2 = 0
 ok, how the solution of (a) will be if : https://www.diigo.com/item/image/2sb3i/y0us

Recognitions:
Homework Help
 Quote by Ammar w ok, how the solution of (a) will be if : https://www.diigo.com/item/image/2sb3i/y0us
Just solve your equation that I presented in my previous post...
 I'm sorry but can you tell me the equation of (a) if the potential change was "-8"? I thought that the equation +8-12+VR2 = 0 is used when the potential change = -8.

Recognitions:
Homework Help
 Quote by Ammar w I'm sorry but can you tell me the equation of (a) if the potential change was "-8"? I thought that the equation +8-12+VR2 = 0 is used when the potential change = -8.
Yes, that's right. The problem is not with your understanding, it's with the problem itself; the resistor is not labeled correctly for the given answers. The resistor should have its potential labeled as "8V", not "-8V", or alternatively, the + and - tags should be reversed.
 aha thank you Mr. gneill