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KVL Exercise  Basic 
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#1
Feb613, 09:30 AM

P: 28

1. The problem statement, all variables and given/known data
Click on the link https://www.diigo.com/item/image/2sb3i/yjim 2. Relevant equations KVL Law Similar Example : https://www.diigo.com/item/image/2sb3i/orwa 3. The attempt at a solution (a) In the left loop : 812+VR2 = 0 VR2 = 20 v (b) In the big loop : 812+79V23+VR1 = 0 812+79V23+1 = 0 V2 = 24 Why is my solution wrong? If I take the right loop for (b) using the right answer for (a) : 4+79V23+1 = 0 V2 = 8 which is true. Is the wrong with the negative voltage (8) ?? thanks. 


#2
Feb613, 09:48 AM

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P: 11,618

Bottom line: assume that the "8V" is really "8V" oriented according to the "+ ". 


#3
Feb613, 10:03 AM

P: 28

thank you
but I see that there is no difference if it was "+8" instead of "8" ??? 


#4
Feb613, 10:15 AM

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P: 11,618

KVL Exercise  Basic
For part (a) your equation summing the potential drops would become: +812+VR2 = 0 


#5
Feb613, 10:27 AM

P: 28

ok, how the solution of (a) will be if :
https://www.diigo.com/item/image/2sb3i/y0us 


#6
Feb613, 10:35 AM

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#7
Feb613, 10:44 AM

P: 28

I'm sorry
but can you tell me the equation of (a) if the potential change was "8"? I thought that the equation +812+VR2 = 0 is used when the potential change = 8. 


#8
Feb613, 11:41 AM

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#9
Feb613, 11:44 AM

P: 28

aha
thank you Mr. gneill 


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