curvature of a trajectory


by rsaad
Tags: curvature, trajectory
rsaad
rsaad is offline
#1
Feb8-13, 09:55 AM
P: 77
Hi!
Can someone please explain how does the limit in the attachment equals the curvature of a trajectory? I do not understand it. Why is it defined this way?

ζ=dx/dl and it is in the direction of T.

Thank you!
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vanhees71
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#2
Feb8-13, 01:06 PM
Sci Advisor
Thanks
P: 2,141
It tells you, how much the direction of the tangent vector changes per unit length, when you walk along the curve. The larger this number (of dimension 1/length), the more your direction changes per unit path length. Thus it makes sense to call this the curvature. One can also show that it is an invariant wrt. to the choice of coordinates and parametrizations of the curve, because it can be derived from the curvature tensor.
mfb
mfb is online now
#3
Feb8-13, 01:09 PM
Mentor
P: 10,830
You can check how ##\tau## and ##l## look for a circle - and all curves (with a well-defined curvature) locally look like circles.
Alternatively, see Wikipedia, or any textbook.


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